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mihalych1998 [28]
3 years ago
11

Simplify the following expression. (z^3)^4(q^3)^0

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
4 0
Any number raised to the power of 0 is 1.
(z^3)^4(q^3)^0 = (z^3)^4 = z^(3 x 4) = z^12
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Step-by-step explanation:

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Explain how to use a coordinate plane to find the area of a rectangle with vertices (–4, 9), (–4, –3), (–1, –3), and (–1, 9). wh
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the formula for area of a rectangle is

Area = length x width

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Se tiene un rectángulo cuya base mide el doble que su altura y su área es 12
irina [24]

Answer:

Part 1) The perimeter is  P=6\sqrt{6}\ cm

Part 2) The diagonal is d=\sqrt{30}\ cm

Step-by-step explanation:

<u><em>The question in English is</em></u>

You have a rectangle whose base is twice the height and its area is 12

square centimeters. Calculate the perimeter of the rectangle and its diagonal

step 1

Find the dimensions of rectangle

we know that

The area of rectangle is equal to

A=bh

A=12\ cm^2

so

bh=12 ----> equation A

The base is twice the height

so

b=2h ----> equation B

substitute equation B in equation A

(2h)h=12\\2h^2=12\\h^2=6\\h=\sqrt{6}\ cm

Find the value of b

b=2\sqrt{6}\ cm

step 2

Find the perimeter of rectangle

The perimeter is given by

P=2(b+h)

substitute

P=2(2\sqrt{6}+\sqrt{6})\\P=6\sqrt{6}\ cm

step 3

Find the diagonal of rectangle

Applying the Pythagorean Theorem

d^2=b^2+h^2

substitute

d^2=(2\sqrt{6})^2+(\sqrt{6})^2

d^2=30

d=\sqrt{30}\ cm

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