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Korvikt [17]
3 years ago
15

If sin t = -8/17 and t is a quadrant III angle, find cot t

Mathematics
1 answer:
nirvana33 [79]3 years ago
8 0

Answer:cot t = 1.875

sin t=\frac{-8}{17} but sin²t + cos²t = 1 ⇔ cos²t = 1 - sin²t

⇔cos t = \sqrt{1-sin^{2}t }=\sqrt{1-(\frac{-8}{17})^{2}  }=|\frac{15}{17}|

but  t is a quadrant III angle => cos t = \frac{-15}{17}

=> cot t = \frac{-15}{17}:\frac{-8}{17}=\frac{15}{8}=1.875

Step-by-step explanation:

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