Answer:
How many drinks should be sold to get a maximal profit? 468
Sales of the first one = 345 cups
Sales of the second one = 123 cups
Step-by-step explanation:
maximize 1.2F + 0.7S
where:
F = first type of drink
S = second type of drink
constraints:
sugar ⇒ 3F + 10S ≤ 3000
juice ⇒ 9F + 4S ≤ 3600
coffee ⇒ 4F + 5S ≤ 2000
using solver the maximum profit is $500.10
and the optimal solution is 345F + 123S
Answer: 22%
Step-by-step explanation:
The equation for this is (n-2) x 180
Replace n with the number of sides:
a. 9: (9-2) x 180 = 7 x 180 = 1,260
b. 19: (19-2) x 180 = 17 x 180 = 3,060
Answer:
Step-by-step explanation:
5+1+3+8+2=19
3/19 = 16%
