Answer:
Option A
Step-by-step explanation:
The complete question is attached here
The rate of increase of bacterial population be K
As we know
where Y is the final population. In this case it is 1000
K is the rate of increase of population i.e 3 times per hour
T is the time in hours
Y0 is the initial population = 5
Substituting the given values, we get -
Taking log on both sides, we get -
ln 
= ln 
T = 2.084 hours
hence, option A is correct
<h3>
Answer: -3.71</h3>
========================================================
Explanation:
You'll need to use a T table to answer this question. Your stats textbook should have such a table in the back appendix section.
If your textbook doesn't have the proper table, or you don't have your textbook with you, then I recommend searching online for "t table" and you should have tons of free options to choose from.
In the table you'll look for the degrees of freedom row 6, since the degrees of freedom are equal to n-1. In this case, n = 7.
In this row, locate the column labeled "alpha = 0.005" and you'll be looking at "one tail". The value in this row and column is roughly 3.707
Since we're doing a left tailed test and we want P(t < C) = 0.005, where C is the critical value we're after. This must mean C < 0. So C = -3.707 approximately. Round this to two decimal places and we end up with -3.71
Answer: cotθ
<u>Step-by-step explanation:</u>
tanθ * cos²θ * csc²θ
= 
= 
= cotθ
Answer: B
<u>Step-by-step explanation:</u>
The parent graph is y = x²
The new graph y = -x² + 3 should have the following:
- reflection over the x-axis
- vertical shift up 3 units
Answers:
- a. Quadrant II
- b. negative
- c.
- d. C
- e.
<u>Explanation:</u>
a) Quadrant 2 is: 
b) In Quadrant 2, cos is negative and sin is positive, so tan is negative
c) 
=
d) the reference line is above the x-axis so it is negative --> 
e) 
