<span>Use a proportion:
x/(5 1/2) = 50/4
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x = (11/2)(50/4)
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x = 550/8
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x = $68.75</span>
Answer:
1
Step-by-step explanation:
Choose two points on the line: (-5, 0) and (0, 5)
Let the first point 
= (-5, 0)
Let the second point 
= (0, 5)
Use the gradient formula:
----------------------------------------------------------------------------------------------------
If you want to find the equation of the line, use the point-gradient form of a linear equation: 
(where 
is the gradient and is a point on the line)
Substituting the values into the formula:
Therefore, the equation of the line is y = x + 5
The number of students would not change between before the test and after the test. 3+8 and 4+7 both = 11 so finding out how many students would equal one ratio can then be used to find how many equal 3 and 8.
If 92 students are equal to 4 in the ratio, then 1 in the ratio is worth 23 students. This is important as then when you times 23 by 7 you find out how many students there are in the regular maths class, 161 students. Plussing these two together gives you a total of 253 students.
Using this 253 you can divide it by 11 to find out how much 1 number would be in the ratio, it equals 23. Using this you can then times 23 by both 3 and 8 to find the original class sizes, 3x23 = 69, and 23x8 = 184.
Making the origional class size of the advaced class 69 studnets, and the regular maths class size 184.
Answer:
HAVE A NICE DAY :)))
Step-by-step explanation:
thank
Answer:
C. 15m
Step-by-step explanation:
if ABCD and EFGH are congruent that means that they are equivalent to each other. If side FG is the base of that trapizoid, and side CD is the base with the measurement of 15m, then we are left to believe that side FG is 15m
