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eimsori [14]
3 years ago
5

You have a bag that contains 6 red marbles and 3 blue marbles. You randomly choose one of the marbles. Without replacing the fir

st marble, you choose a second marble. Find the probability of the events.
Mathematics
1 answer:
cestrela7 [59]3 years ago
5 0

Answer:

12/27

Step-by-step explanation:

You have a bag that contains 6 red marbles and 3 blue marbles. You randomly choose one of the marbles. Without replacing the first marble, you choose a second marble. Find the probability of the events.

Let the total number of marbles = 6 red marble + 3 blue marbles = 9 marbles

You randomly choose one of the marbles. Without replacing the first marble, you choose a second marble. Find the probability of the events.

Assume all you picked is red( without replacement)

= 6/9 × 5/9

= 30/81

= 10/27

Assume all you picked is blue( without replacement)

= 3/9 × 2/9

= 6/81

= 2/27

The probability of the events is calculated as:

All red or All blue

= 10/27 + 2/27

= 12/27

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Step-by-step explanation:

A line that cuts a circle at two points is called "secant".

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