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3 years ago

Use the Quadratic Formula to Solve: 8x^2+4x-16= -x^2

Mathematics

1 answer:

Harlamova29_29 [7]3 years ago

8 0

Solve the equation for x by finding a, b and c of the quadratic then applying the quadratic formula

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Simplify 7 - (-4) + 3(-6)

jeka94

Answer:

-7

Step-by-step explanation:

7 - (-4)= 11

3(-6)= -18

=-7

8 0

3 years ago

Read 2 more answers

URGENT HELP What is the equation of the line that passes through the point (-7, -4) and has a

shepuryov [24]

The final equation is:

$y=x+3$

Further explanation:

The general form of equation of a line in slope-intercept form is:

$y=mx+b$

Here m is the slope

Given

m=1

(x,y) = (-7,-4)

$Putting\ the\ value\ of\ slope\ in\ equation\\y=(1)(x)+b\\y=x+b$

To find the value of b, we have to put the point in the equation

$-4=-7+b\\-4+7=b\\b=3$

The final equation is:

$y=x+3$

Keywords: Slope-intercept form, equation of line

Learn more about slope-intercept form at:

#LearnwithBrainly

7 0

3 years ago

Which equations results from adding the equations in this system?<br> x+6y=9<br> -x+2y=-15

UkoKoshka [18]

Answer:

8y = -6

Step-by-step explanation:

Simply add the equations as you would numbers.

The 'x's cancel each other out. The 'y's add together as normal numbers.

9 + (-15) = -6

Hope that this helps!

4 0

3 years ago

This is hard........ help please?

anygoal [31]

Answer: C.

There are 215 total students in the band.

There are 27 seniors in the band.

The probability is found by dividing the number of seniors in the band by the TOTAL number of students in the band.

P(S|B) = 27/215 = 0.1255813953

You have to round off the answer too the nearest tenth.

P(S|B) = 0.13

6 0

3 years ago

Using the laws of indices simplify 625^3/8 ×5^1/2÷ 25

Oxana [17]

Answer:

Step-by-step explanation:

$\huge {625}^{ \frac{3}{8} } \times {5}^{ \frac{1}{2} } \div 25 \\ \\ = \huge {( {5}^{4})}^{ \frac{3}{8} } \times {5}^{ \frac{1}{2} } \div {5}^{2} \\ \\ = \huge{5}^{ \cancel4 \times \frac{3}{ \cancel8 \: \: \red{ \bold 2}} } \times {5}^{ \frac{1}{2} } \div {5}^{2} \\ \\ \huge= {5}^{ \frac{3}{2} } \times {5}^{ \frac{1}{2} } \div {5}^{2} \\ \\ \huge= {5}^{ \frac{3}{2} + \frac{1}{2}} \div {5}^{2} \\ \\ \huge= {5}^{ \frac{4}{2} } \div {5}^{2} \\ \\ \huge= {5}^{ 2 } \div {5}^{2} \\ \\ \huge= {5}^{ 2 - 2 } \\ \\ \huge= {5}^{ 0 } \\ \\ \huge= 1$

5 0

3 years ago