Based on the lengths, the cheerleaders' banner is scaled down by a factor of 4.
So, 44 ÷ 4 = 11.
For the perimeter, 156 ÷ 4 is 39.
For the area, you have to do A=bh
(Area = base × height)
The base (length) is 11 inches, multiply that by two to get 22 inches which is the amount for both lengths. If the total perimeter is 39, you have to subtract 22 from that to get the remaining inches which is 17.
17÷2= 8.5 inches. The height is 8.5.
Now you can plug them in
A=bh
A=(11)(8.5)
A=93.5 in^2
The final answer is:
Area = 93.5 in^2
Length = 11 in
Perimeter = 39 in
I hope that helps!
Answer:
Most people found the probability of just stopping at the first light and the probability of just stopping at the second light and added them together. I'm just going to show another valid way to solve this problem. You can solve these kinds of problems whichever way you prefer.
There are three possibilities we need to consider:
Being stopped at both lights
Being stopped at neither light
Being stopped at exactly one light
The sum of the probabilities of all of the events has to be 1 because there is a 100% chance that one of these possibilities has to occur, so the probability of being stopped at exactly one light is 1 minus the probability of being stopped at both lights minus the probability of being stopped at neither.
Because the lights are independent, the probability of being stopped at both lights is just the probability of being stopped at the first light times the probability of being stopped at the second light. (0.4)(0.7) = 0.28
The probability of being stopped at neither is the probability of not being stopped at the first light, which is 1-0.4 or 0.6, times the probability of not being stopped at the second light, which is 1-0.7 or 0.3. (0.6)(0.3) = 0.18
Step-by-step explanation:
X/0.5 = 24
X/0.5(0.5) = 24(0.5)
X = 12
Answer:
Step-by-step explanation:
Given that acceleration of an object is
is the solution to the differential equation
Since v(0) =7
we get ln 7 = C
Hence 
since velocity is rate of change of distance s we have
![v=\frac{ds}{dt} =7e^{-2t}\\s= [tex]s(t) =\frac{-7}{2} (e^{-2t})+C)[](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bds%7D%7Bdt%7D%20%3D7e%5E%7B-2t%7D%5C%5Cs%3D%20%5Btex%5Ds%28t%29%20%3D%5Cfrac%7B-7%7D%7B2%7D%20%28e%5E%7B-2t%7D%29%2BC%29%5B)
substitute t=0 and s=0
So solution for distance is
Answer:
1. Rectangle
2. 376.8 cm
3. 379.94 square feet
4. –4 and 4
Step-by-step explanation:
A square is always a rectangle.
If a wheel has a radius of 15 cm, it would travel approximately 376.8 cm per 4 revolutions.
If the diameter of a circular garden is 22 feet, the approximate area of the garden is 379.94 square feet.
The solutions to the equation y2 – 1 = 15 is –4 and 4.
