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2 years ago

14

When does a compound inequality with OR have a solution that is the entire number line? Can the solution be bounded to one side?

On two sides? Can there be no solution?

1 answer:

dalvyx [7]2 years ago

6 0

Answer:

Concept: Algebraic Analysis

$\geqslant \: \: \: \: \: \: \: \: \: \: \leqslant$
Those two symbols indicate one solution
$< \: \: \: \: \: \: \: >$
Those symbols indicate a range of values
$x < 15 < x$
Indicates two bounded answers
In an inequality there is always a solution

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Select the correct answer.

neonofarm [45]

The answer is 6 hope this helps

3 0

3 years ago

What would the graph of 10x + 7y < 49 look ?

navik [9.2K]

Answer: The graph is attached.

Step-by-step explanation:

1. Solve for y, as following:

$10x+7y$

2. The equation of the line in slope intercept form is:

$y=mx+b$

Where m is the slope and b is the y-intercept.

3. In this case the equation of the line is:

$y=-\frac{10}{7}x+7$

then:

$m=-\frac{10}{7}\\\\b=7$

4. Find the x-intercept. Make y=0. Then:

$0=-\frac{10}{7}x+7\\\frac{10}{7}x=7\\x=4.9$

5. Then, plot the line that passes through the points (0,7) and (4.9, 0).

6. The symbol of the inequality is < therefore, the line must be dashed and indicates that the region under the line must be shaded.

Then you obtain the graph attached.

8 0

3 years ago

Read 2 more answers

Determine whether the three segment lengths will produce a triangle. Type yes or no in the space provided.

tresset_1 [31]

Answer:

20 , 20 , 30 will produce a triangle

Step-by-step explanation:

* Lets study how to know if the lengths of the three segments

can formed a triangle

- It is a fact that in any triangle the sum of the smallest two sides

must be greater than the largest side

- Lets study some examples

# If the lengths of the three segments are 5 , 6 , 7

∵ 5 and 6 are the smallest

∴ 5 + 6 = 11

∵ 11 > 7 ⇒ the sum greater than the 3rd side

∴ 5 , 6 , 7 can formed a triangle

# If the lengths of the three segments are 5 , 7 , 12

∵ 5 and 7 are the smallest

∴ 5 + 7 = 12

∵ 12 = 12 ⇒ the sum equal the 3rd side

∴ 5 , 7 , 12 can not formed a triangle

# If the lengths of the three segments are 10 , 12 , 24

∵ 10 and 12 are the smallest

∴ 10 + 12 = 22

∵ 22 < 24 ⇒ the sum less than the 3rd side

∴ 10 , 12 , 24 can not formed a triangle

* Now lets solve the problem

∵ The length of the three segments are 20 , 20 , 30

∵ 20 and 20 are the smallest

∴ 20 + 20 = 40

∵ 40 > 30 ⇒ the sum greater than the 3rd side

∴ 20 , 20 , 30 will produce a triangle

5 0

2 years ago

Please help: write each equation in exponential form

Setler [38]

Answer:

$4^{4}=256$

Step-by-step explanation:

<u>Rewrite log4256=4 in a different form:</u>

<u /> $4^{4}=256$

4 0

2 years ago

I need some help with this calculus 1 question.

Cerrena [4.2K]

Answer:

(a) f'(1)=-4

(b) y+4x-4=0

Step-by-step explanation:

<u>Tangent Line of a Function</u>

Given f(x) a real differentiable function in x=a, the slope of the tangent line of the function in x=a is given by f'(x=a). Where f' is the first derivative of f.

We are given

$y=x-x^5$

The derivative is

$y'=1-5x^4$

(a) The slope of the tangent line at (1,0) is

$f'(1)=1-5\cdot 1^4=-4$

$f'(1)=-4$

(b) The equation of the tangent line can be found with the general formula of the line:

$y-y_o=m(x-x_o)$

Where m is the slope and the point (xo,yo) belongs to the line. We have m=-4, xo=1, yo=0, thus

$y-0=-4(x-1)$

Or, equivalently

$y+4x-4=0$

3 0

2 years ago