C) will not effected (the most frequent is still 600$)
Hey there
__________
The correct answer is
Whatever each CD costs, what each person paid is that cost times the number of CDs purchased (no sales tax for this problem).
So, the price of one CD is a factor of $66 (a number of $ that divides $66 evenly).
In theory, it could be $1, $2, $3, $6, $11, $22, $66.
It could even be $0.50, $0.25, $0.20, $0.10, $0.05,...
Also, the price of one CD must be a factor of $54. such as $54,$27,$18,$9,$6,$3,$2,$1,... .
You are looking for the most that price could be.
The grew greatest price that is in both lists is $6.
How can you make those lists?
You can start with the total price, then the price divided by 2, by 3, by whatever whole number you can divide it.
Otherwise, you could find the greatest common factor of 66 and 54
from the prime factorization of both numbers.
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Hope this helps you
Answer: An arithmetic sequence is of the form:
aₙ = a₀ + (n -1)*d
So the difference between a term and the nextone is always the same, and in our case the numbers are 5,8,13,21,34,55.
The distance between the numbers is not constant, so this is not a arithmetic sequence.
a geometric sequence is of the form: aₙ = a*rⁿ
So the therms grow exponentially.
here a₀ = a*r⁰ = a = 5.
a₁ = a*r¹ = 5*r = 13, then r = 13/5 = 2.6
a₂ = a*r² = 5*2.6*2.6 = 33.8, so here we can see that this is not our series, so our series isn't geometric.
So the answer for the first part is neither.
Now, the sequence is 5,8,13,21,34,55, ...
you can see that
5 + 8 = 13
13 + 8 = 21,
21 + 34 = 55
So our sequence is of the form: aₙ = aₙ₋₁ + aₙ₋₂.
then, the next term will be: 55 + 21= 76.
You can cross multiply and the answer would be 100/9
9/10=10/k
100=9k
k=100/9
