There are 8 students on the school chess team. They need to raise at least $760 for a field trip. Their advisor says they still
need to raise 85% of the funds, and she wants each of them to raise an equal share of the money still needed.
Diego wrote and solved the inequality 8m + 0.85(760)> to find-
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the least amount of money, m, each student on the chess team still needs to raise. He says the solution is m > $14.25
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Describe and correct Diego’s error.
Diego wrote and solved the inequality 8m + 0.85(760)> to find-
-
the least amount of money, m, each student on the chess team still needs to raise. He says the solution is m > $14.25
-
Describe and correct Diego’s error.
1 answer:
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Answer:
b = 3, which is an extraneous solution because if we replace b = 3 in the equation, we must be 5/0 and 30/0, and there is division by 0.
Step-by-step explanation:
The minus common multiply must be (b-3)*(b+3) = b² - 9
7b - 21 + 5b + 15 = 10b
2b = 6
b = 3
Which is an extraneous solution because if we replace b = 3 in the equation, we must be 5/0 and 30/0, and there is division by 0. So this solution is invalid.