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Nadusha1986 [10]
3 years ago
7

X + 2x + 12y + 4 Using the expression shown, add like terms and produce an equivalent expression.

Mathematics
2 answers:
Paul [167]3 years ago
7 0

Answer:

3x + 12y + 4

I dont really know how to explain but since there is an X at the and of the 2, you can add X + 2x to get 3x. Since 3x, 12y, and 4 are not alike, this is the simplest form.

Aleksandr-060686 [28]3 years ago
3 0

Answer: 3x+12y+4

Step-by-step explanation:

The only like terms are the x+2x so we add them to get the simplfied answer

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levacccp [35]

Answer:

D.) 4

Step-by-step explanation:

Your highest exponent is your degree.

Its easier if you put the polynomial in order:

27x^4+15x^3+63x+35

5 0
3 years ago
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Find a point-slope form for the line that satisfies the stated conditions.
Yakvenalex [24]

Answer:

y=6x+41

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3 years ago
Simon can see two lights, light A and light B.
xz_007 [3.2K]

Answer:

2 Times

Step-by-step explanation:

Simon can see two lights A and B

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First, we determine the next time both lights will flash together.

This is done by finding the Least Common Multiple of 15 and 18.

15=3X5

18=2X3^2

LCM of 15 and 18=2X3^2X5=90

This means that lights A and B will first flash together after 90 seconds.

Now, 240/90=2.\overline{6} seconds

Therefore, the number of times more both light will flash together in the next 4 Minutes= 2 Times

3 0
3 years ago
I need help for this, thanks
gulaghasi [49]

(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.

---------------------------------------------------------------------------------------

(b) The following functions are positive in quadrant III:

tangent, cotangent

The following functions are negative in quadrant III

cosine, sine, secant, cosecant

A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.

5 0
3 years ago
Pls help am failing <br> Hehehehgshdhdjsjbsvdv
ludmilkaskok [199]

Answer:

should be B

Step-by-step explanation:

7 0
3 years ago
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