Answer:
well if several means 3 then she used 12 pints.
Step-by-step explanation:
3X4=12
4X4=16
5X4=20 and so on.
here we have to find the quotient of '(16t^2-4)/(8t+4)'
now we can write 16t^2 - 4 as (4t)^2 - (2)^2
the above expression is equal to (4t + 2)(4t - 2)
there is another expression (8t + 4)
the expression can also be written as 2(4t + 2)
now we have to divide both the expressions
by dividing both the expressions we would get (4t + 2)(4t - 2)/2(4t + 2)
therefore the quotient is (4t - 2)/2
the expression comes out to be (2t - 1)
Let's begin by listing the first few multiples of 4: 4, 8, 12, 16, 20, 24, 28, 32, 36, 38, 40, 44. So, between 1 and 37 there are 9 such multiples: {4, 8, 12, 16, 20, 24, 28, 32, 36}. Note that 4 divided into 36 is 9.
Let's experiment by modifying the given problem a bit, for the purpose of discovering any pattern that may exist:
<span>How many multiples of 4 are there in {n; 37< n <101}? We could list and then count them: {40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96, 100}; there are 16 such multiples in that particular interval. Try subtracting 40 from 100; we get 60. Dividing 60 by 4, we get 15, which is 1 less than 16. So it seems that if we subtract 40 from 1000 and divide the result by 4, and then add 1, we get the number of multiples of 4 between 37 and 1001:
1000
-40
-------
960
Dividing this by 4, we get 240. Adding 1, we get 241.
Finally, subtract 9 from 241: We get 232.
There are 232 multiples of 4 between 37 and 1001.
Can you think of a more straightforward method of determining this number? </span>
Answer:
-42
Step-by-step explanation:
Following Order of Operations, we have to multiply before subtracting, so
Using order of operations, we get -42.
Answer:
The teenagers spent 4.5 hours per week, on average, on the phone.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 4.5
Sample mean, 
= 4.75
Sample size, n = 15
Alpha, α = 0.05
Sample standard deviation, s = 2
First, we design the null and the alternate hypothesis
We use one-tailed(right) t test to perform this hypothesis.
Formula:
Putting all the values, we have
Now,
Since,
We accept the null hypothesis. Thus, the teenagers spent 4.5 hours per week, on average, on the phone. The sample contradicted the organization's claim.
