We have 60 gallons of 20% antifreeze.
How much 70% antifreeze do we add to get 60% antifreeze?
We'll make "x" the gallons of 70% we must add.
.20 * 60 + .70 x = .60 * (60 + x)
12 + .70x = 36 + .60x
.10x = 24
x = 240 gallons of 70% antifreeze.
Source
1728.com/mixture.htm (see example B)
I need to see the diagrams to tell you.
Answer:
40%
Step-by-step explanation:
15-9=6
6/15=2/5=40/100=40%
1. C
2. A
3. D
4. 62/25
5. 4/33
By the way it is not fair. posting 5 sums for just 7 points. :)
anyway, if it helped u
do click thx.
Your answer would be C. x = 6, y = 5
This is because if you plug the numbers in to the inequality, we get:
(4 × 5) ≥ (3 × 6) + 2
20 ≥ 18 + 2
20 ≥ 20
which is correct.
I hope this helps!
