A function

is periodic if there is some constant

such that

for all

in the domain of

. Then

is the "period" of

.
Example:
If

, then we have

, and so

is periodic with period

.
It gets a bit more complicated for a function like yours. We're looking for

such that

Expanding on the left, you have

and

It follows that the following must be satisfied:

The first two equations are satisfied whenever

, or more generally, when

and

(i.e. any multiple of 4).
The second two are satisfied whenever

, and more generally when

with

(any multiple of 10/7).
It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when

is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.
Let's verify:


More generally, it can be shown that

is periodic with period

.
There is a way and you will find it but not from me
9514 1404 393
Answer:
4
Step-by-step explanation:
Maybe you want the value of 16/f when f=4. Put the value of f where f is and do the arithmetic.

Answer:
u need 2 equation to solve
Step-by-step explanation:
Answer: the observer should consider to eliminate or to retake the third measure.
Explanation:
The four measures taken are 124.53, 124.55, 142.51 and 124.52.
As it can be easily seen, the third measure is much different from the other three. This means that something went wrong during the observation: it can be either the measure taken wrong or that the number was written wrong (if you switch the 2 and the 4 you get a number similar to the other ones).
If the third measure is not considered, an estimate of the mean would place it around 124.5, while if the outlier (the detatched number) is considered an estimate of the mean would increase to about 129.
Therefore, in order to obtain a more reliable mean, the observer should consider to eliminate or to retake the third measure.