Answer:
Therefore the required polynomial is
M(x)=0.83(x³+4x²+16x+64)
Step-by-step explanation:
Given that M is a polynomial of degree 3.
So, it has three zeros.
Let the polynomial be
M(x) =a(x-p)(x-q)(x-r)
The two zeros of the polynomial are -4 and 4i.
Since 4i is a complex number. Then the conjugate of 4i is also a zero of the polynomial i.e -4i.
Then,
M(x)= a{x-(-4)}(x-4i){x-(-4i)}
=a(x+4)(x-4i)(x+4i)
=a(x+4){x²-(4i)²} [ applying the formula (a+b)(a-b)=a²-b²]
=a(x+4)(x²-16i²)
=a(x+4)(x²+16) [∵i² = -1]
=a(x³+4x²+16x+64)
Again given that M(0)= 53.12 . Putting x=0 in the polynomial
53.12 =a(0+4.0+16.0+64)
=0.83
Therefore the required polynomial is
M(x)=0.83(x³+4x²+16x+64)
Answer:
24.
Step-by-step explanation:
With composition of functions (as with the order of operations) we perform what is inside of the parentheses first. So, g(3)=2(3)+2=8 and then f(8)=24.
Answer:
13 m
Step-by-step explanation:
<u>The distance x is:</u>
x = √12² + (13 -8)² = √144 + 25 = √169 = 13 m
Answer:
I believe the answer is transative property. I'm currently taking the test so I'm not 100% sure if I'm right yet.
Step-by-step explanation:
In step one, AGE and HGB are verticle angles since they are opposite of each other. then step two is alternate interior angles because they are interior angles opposite of each other, self-explanatory. the reason I choose the transitive property over the corresponding angles theorem is because the transitive property states: among A B and C, if A=B and B=c then A=C and in this case since AGE=HGB andHGB=CHE then AGE=CHE. I hope this helps and if you know the right answer just put it in the comments, if I'm wrong ofc.
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