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2 years ago

If you can, please help me! I'll give brainliest (if I can.)

Mathematics

1 answer:

dlinn [17]2 years ago

4 0

Answer:

The intersection of the sets A, B, and C is Bird.

Set B contains Fish, Lizard, Turtle, Bird, and Dog.

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There were 450 people at a play. The admission price was $2 for adults and $1 for children. The admission receipts were $680. Ho

vampirchik [111]

Answer:

Adults= 110

Children= 340

Step-by-step explanation:

Given data

let adults be x

and children be y

x+y= 450----------1

2x+y=680---------2

from 1

x= 450-y

put this in 2

2(450-y)=680

900-2y=680

900-680=2y

220=2y

y= 220/2

y= 110

x+110= 450

x= 450-110

x=340

4 0

3 years ago

The students in Mr. Wilson's Physics class are making golf ball catapults. The

Mnenie [13.5K]

Answer:

Part a) About 48.6 feet

Part b) About 8.3 feet

Part c) The domain is $0 \leq x \leq 48.6\ ft$ and the range is $0 \leq y \leq 8.3\ ft$

Step-by-step explanation:

we have

$y=-0.014x^{2} +0.68x$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

where

x is the ball's distance from the catapult in feet

y is the flight of the balls in feet

Part a) How far did the ball fly?

Find the x-intercepts or the roots of the quadratic equation

Remember that

The x-intercept is the value of x when the value of y is equal to zero

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-0.014x^{2} +0.68x=0$

$a=-0.014\\b=0.68\\c=0$

substitute in the formula

$x=\frac{-0.68(+/-)\sqrt{0.68^{2}-4(-0.014)(0)}} {2(-0.014)}$

$x=\frac{-0.68(+/-)0.68} {(-0.028)}$

$x=\frac{-0.68(+)0.68} {(-0.028)}=0$

$x=\frac{-0.68(-)0.68} {(-0.028)}=48.6\ ft$

therefore

The ball flew about 48.6 feet

Part b) How high above the ground did the ball fly?

Find the maximum (vertex)

$y=-0.014x^{2} +0.68x$

Find out the derivative and equate to zero

$0=-0.028x +0.68$

Solve for x

$0.028x=0.68$

$x=24.3$

<em>Alternative method</em>

To determine the x-coordinate of the vertex, find out the midpoint between the x-intercepts

$x=(0+48.6)/2=24.3\ ft$

To determine the y-coordinate of the vertex substitute the value of x in the quadratic equation and solve for y

$y=-0.014(24.3)^{2} +0.68(24.3)$

$y=8.3\ ft$

the vertex is the point (24.3,8.3)

therefore

The ball flew above the ground about 8.3 feet

Part c) What is a reasonable domain and range for this function?

we know that

A reasonable domain is the distance between the two x-intercepts

$0 \leq x \leq 48.6\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 48.6 feet

A reasonable range is all real numbers greater than or equal to zero and less than or equal to the y-coordinate of the vertex

we have the interval -----> [0,8.3]

$0 \leq y \leq 8.3\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 8.3 feet

8 0

2 years ago

ANSWER QUICK!!! IM TAKING A TEST AND I WILL MARK BRAINLIEST!!!

gtnhenbr [62]

Answer:

C = 5Q

Step-by-step explanation:

C = Length of Cloth in Meters (C)

Q = Number of Quilts Made (Q)

C = 5Q

Change C for the numbers under (Length of Cloth in Meters (C))
Nad change Q for the numbers under (Number of Quilts Made (Q))

So the new equations would be:

0 = 5(0) ---------> 0 = 0

5 = 5(1) ---------> 5 = 5

10 = 5(2) ---------> 10 = 10

15 = 5(3) ---------> 15 = 15

20 = 5(4) ---------> 20 = 20

25 = 5(5) ---------> 25 = 25

So the only option that amkes sense is (C = 5Q)

3 0

2 years ago

Please help

Montano1993 [528]

Answer:

M = 2x² - (ax/3) + by

B = - 3x²y + (xy³/3) - cy

Step-by-step explanation:

Equation 1 is

2x² - (1/3)ax + by - M = 0

M = 2x² - (ax/3) + by

Equation 2

3x²y - (1/3)xy³ + cy + B = 0

B = - 3x²y + (xy³/3) - cy

Hope this Helps!!!

7 0

3 years ago

IM DESPERATE

telo118 [61]

You can scan it on brainly, It’ll help you

7 0

2 years ago

If you can, please help me! I'll give brainliest (if I can.)​

If you can, please help me! I'll give brainliest (if I can.)