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2 years ago

If you can, please help me! I'll give brainliest (if I can.)

Mathematics

1 answer:

dlinn [17]2 years ago

4 0

Answer:

The intersection of the sets A, B, and C is Bird.

Set B contains Fish, Lizard, Turtle, Bird, and Dog.

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What is the value of discontinuity of x^2+8x+4/x^2-x-6? Choices:

Morgarella [4.7K]

Answer:

-2

Step-by-step explanation:

Hello,

First of all, let's check the denominator.

$x^2-x-6 \ \ \text{ *** How to factorise it ...? ***}\\\\\text{*** The product of the roots is -6=-2*3 and their sum is 1 ***}\\\\x^2-x-6=x^2-3x+2x-6=x(x-3)+2(x-3)=(x+2)(x-3)$

Now, let's see the numerator.

$x^2+8x+4 \ \text{ *** -2 is not a zero as ***}\\\\(-2)^2+8*(-2)+4=4-16+8=-4\\\\\text{*** 3 is not a zero as ***}\\\\3^2+8*3+4=9+24+4=37\\$

So we cannot factorise the numerator with (x+2) or (x-3)

Then, -2 and 3 are the the discontinuities of the expression.

There is only -2 in the list, this is the correct answer.

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

3 0

2 years ago

Which group of numbers is listed from least to greatest?

Tom [10]

Answer:

a) -8, -6, -1, 5,8

Step-by-step explanation:

*View the image attached*

As you can see, the further left on the number line, the smaller the number becomes.
The further right on the number line, the bigger the number becomes.

Hope this helps!

3 0

1 year ago

Landrie is selling bracelets and earrings to make money for a SUP (Standup Paddle Board) has a goal to earn $500. She plans on s

victus00 [196]

Answer:

120 earrings and 70

Step-by-step explanation:

3 0

3 years ago

Where the square root of 7 be located on the number line below?

Semmy [17]

Answer: p and q

Step-by-step explanation: 2.64 x 2.64 = 6.9696

7 0

3 years ago

How many whole numbers are there<br>between 181 and 200

emmainna [20.7K]

Answer:

Step-by-step explanation:

200−181 = 19

There are 19 whole numbers between 181 and 200.

3 0

2 years ago

If you can, please help me! I'll give brainliest (if I can.)​

If you can, please help me! I'll give brainliest (if I can.)