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jasenka [17]
2 years ago
7

|1/2- x/3|=5/6. Solve for x. There is (most likely) 2 answers

Mathematics
1 answer:
ira [324]2 years ago
4 0

Answer:

Ans is -1

Step-by-step explanation:

Hope the picture will help you..

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Which equation can be used to calculate the area of the shaded triangle in the figure below?
lozanna [386]

Answer:

A

Step-by-step explanation:

The area (A) of a triangle is calculated using the formula

A = \frac{1}{2} bh ( b is the base and h the perpendicular height )

here b = 14 and h = 4, hence

A = \frac{1}{2} (14 × 4) = 28

7 0
3 years ago
ASAP!<br> lines p and q are parallel what is the sum of the degrees measure of angles x and y
blagie [28]
90? there’s a 45 degree angle at the bottom left and it looks like the same angle as x and y
7 0
2 years ago
Based only on the information given in the diagram, which congruence
Wewaii [24]

Answer:

Option B

Option E

Step-by-step explanation:

By the use of following postulates we can prove the two right triangles to be congruent.

1). HA - [Equal hypotenuse and an cute angles]

2). LL - [Two legs should be equal]

3). LA - [One leg and one angle must be equal]

4). ASA - [Two angles and the side containing these angles should be equal]

In the given right triangles,

1). OJ ≅ IL

2). ∠O ≅ ∠I

3). ∠J ≅ ∠L

Therefore, two postulates HA, ASA will be applicable for the congruence of the two triangles given.

Options A and E will be the answer.

3 0
3 years ago
Read 2 more answers
1. Consider the rational numbers 4/13 and 3/10.
Murljashka [212]

A)4/13 would be the larger number since if you were to try to add them, 4/13 = 40/130 and 3/10 = 39/130, 40/130 > 39/130

B) A rational number between them would be 39.5/130.

5 0
3 years ago
Use a table of values with at least 5 values to graph the following function:
34kurt

The given expression :

y=(\frac{1}{2})^x

For coordinates:

put x = 0 then :

\begin{gathered} y=(\frac{1}{2})^0 \\ y=1 \end{gathered}

Coordinate : (x, y) = (0, 1)

Put x= 1 and simplify :

\begin{gathered} y=(\frac{1}{2})^1 \\ y=\frac{1}{2} \\ y=0.5 \end{gathered}

Coordinate : (x, y) = ( 1, 0.5)

Put x = (-2) and simplify :

\begin{gathered} y=(\frac{1}{2})^{-2} \\ y=\frac{1^{-2}}{2^{-2}} \\ y=\frac{2^2}{1^2} \\ y=2^2 \\ y=4 \end{gathered}

Coordinate : (x, y) = ( -2, 4)

Put x = (-3) and simplify :

\begin{gathered} y=(\frac{1}{2})^{-3} \\ y=\frac{1^{-3}}{2^{-3}} \\ y=\frac{2^3}{1^3} \\ y=2^3 \\ y=8 \end{gathered}

Coordinate : (x, y) = (-3, 8)

Substitute x = (-1) and simplify :

\begin{gathered} y=(\frac{1}{2})^x \\ y=(\frac{1}{2})^{-1} \\ y=\frac{1^{-1}}{2^{-1}} \\ y=\frac{2}{1} \\ y=2 \end{gathered}

Coordinate : (x, y) = ( -1, 2)

So, the coordinates are :

The graph is :

4 0
1 year ago
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