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Inessa05 [86]
3 years ago
10

Calculate the quotient.

Mathematics
1 answer:
Neko [114]3 years ago
4 0

A) 3/4 ÷ 5 1/5.

Answer:

\frac{15}{104}

B) 3/7 ÷ 2 1/2.

Answer:

\frac{6}{35}

C) 5/8 ÷ 6 5/6.

Answer:

\frac{15}{164}

D) 8 3/10 ÷ 5/8.

Answer:

13 \frac{7}{25}

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Write five names for 64 .
Natali [406]
In word form: Sixty four
in expanded form: 6x10 + 4x1
in place value form: 6 tens + 4 ones
in Roman numeral form: LXIV
in Arabic numeral form: ٦٤
4 0
3 years ago
Read 2 more answers
there are 75 students on the sapphire team and 1/5 of them are in the band . how many students are in band?
faltersainse [42]

Answer:

15

Step-by-step explanation:

75/5 = 15

This spilts the 75 students into 5 different groups and each one has 15 which is 1/5 of the students

6 0
1 year ago
Which statements can be used to justify the fact that two right angles are supplementary? Select two options.
agasfer [191]

Answer:

A right angle measures 90°.

A supplementary angle is twice the measure of a complementary angle.

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Suppose that we want to test the hypothesis with a significance level (alpha) of .05 that the climate has changed since industri
saw5 [17]

Answer: we reject the initial claim

(50. 3802, 51.6198)

Step-by-step explanation:

A)

The initial statement is that the mean temperature throughout history is 50°

This is the null hypothesis and it is denoted as H'

H': u = 50.

After taking a sample of 40 years, we realized that the mean temperature is 51°.

This is the alternative hypothesis, in contradiction to the alternative.

The alternative hypothesis is denoted as H1

H1: u > 50 ( upper tailed).

Sample size (n) = 40

Sample mean (x) = 51

Population standard deviation (σ) = 2

We use a z test to get the value of the test statistics.

We are using a z test because sample size is greater than 30 ( n = 40) and population standard deviation is given.

Z score = x - u/ (σ/√n)

Z score = 51 - 50 / (2/√40)

Z score = 1 / 0.3162

Z score = 3.16

Our level of significance is 5%, and the critical value at this level of significance is 1.645.

By comparing the z score relative to the critical value, since our z score is greater than 1.645, it implies that we are in the rejection region hence we reject the initial claim.

B)

We are to construct a 95% confidence interval for population mean temperature.

For upper limit

u = x + Zα/2 ×(σ/√n)

Where Zα/2 = 1.96 which is the critical value for a two tailed test at 5% level of significance.

For upper limit, we have that

u = 51 + 1.96 × (2/√40)

u = 51 + 1.96 (0.3162)

u = 51 + 0.6198

u = 51.6198.

For lower limit, we have that

u = 51 - 1.96 × (2/√40)

u = 51 - 1.96 (0.3162)

u = 51 - 0.6198

u = 50. 3802.

Hence the 95% confidence level for mean temperature is given as (50. 3802°, 51.6198°)

7 0
3 years ago
HELP PLEASE. Write an equation for the graph shown. Be sure to use slope-intercept form
Leya [2.2K]

Answer:

-3x + 5

Step-by-step explanation:

"Rise over Run"

(0, 5) => (1,2): Goes down (negative slope) 3 units and right 1 unit.

The Y intercept is 5 so the constant is 5.

5 0
3 years ago
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