Answer:
At the time of launch height of the object was 60 meters.
Step-by-step explanation:
An object was launched from a platform and its height was modeled by the function,
h(x) = -5x² + 20x + 60
Where x = time or duration after the launch
At the time of launch, x = 0
So, by putting x = 0 in this equation,
h(0) = -5×(0) + 20×(0) + 60
h(0) = 60
Therefore, at the time of launch height of the object was 60 meters.
Answer: -3 2/3x - 1
Step-by-step explanation:
-2/3x + 5(3/5 - 3/5x) - 12 / 6 * 2
First distribute
-2/3x + 3 - 3x - 12 / 6 * 2
Now divide 12 by 6
-2/3x + 3 - 3x -2 * 2
Now multiply -2 by 2
-2/3x + 3 - 3x - 4
Now subtract 3x from -2/3x
-3 2/3x + 3 - 4
Now subtract 4 from 3
-3 2/3x - 1
Answer:
D
Step-by-step explanation:
Answer:
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Answer:
6.14125(0.15) = 0.9211875 (below 1)
6.14125 - 0.92118 = 5.22007
Step-by-step explanation:
Given data
1. 10(.15)=1.5
2. 10-1.5=8.5
3. 8.5 (.15)=1.275
4. 8.5-1.275=7.225
continuation the sequence
5) 7.225 (0.15) = 1.08375
6) 7.225 - 1.08375 = 6.14125
7) <u> 6.14125(0.15) = 0.9211875 (below -one)</u>
8 ) <u> 6.14125 - 0.9211875 = 5.2200625 (get number 5)</u>
9) 5.2200625(0.15) = 0.783009
10) 5.2200625 - 0.783009 = 4.4370532
