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Talja [164]
3 years ago
13

Prove that sin^2x+sinx cosx\tanx​

Mathematics
1 answer:
mafiozo [28]3 years ago
6 0

Answer:

pls do a flie because I can't understanf

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In ΔMNO, m = 780 inches, o = 760 inches and ∠O=164°. Find all possible values of ∠M, to the nearest degree.
Mademuasel [1]

Answer:

So the answer is both

180 and 328 (but it may or may not show you "not possible, if so, then you got it right)

Step-by-step explanation:

SinA/a= SinB/b

1. SinM/780 = Sin164/760

2. 780sin164/760 = 0.2828909704

3. M = sin^-1 (0.2828909704)= 16.4328229 or 16

Check for possibility

180-16= 164

164 + 16= 180 (not possible)

164 + 164= 328 (not possible)

4 0
3 years ago
Read 2 more answers
Solve the system of equations<br> 3x + y = 3<br> x + y = 2
Pachacha [2.7K]

Answer:

(1/2, 3/2)

Step-by-step explanation:

solve the 1st variable in one of the equations and then substitute it and the result will be turned into the other equation.

4 0
3 years ago
Interpret the y-intercept of the graph
Svetlanka [38]

Answer:

answer is A

Step-by-step explanation:

5 0
3 years ago
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Roma selects cards from a standard of 52 cards. Once a card is selected, it is not replaced. Find the probability of each outcom
meriva

Given:

A card is selected randomly from a standard deck of 52 cards.

To find:

The probability of each outcome.

a. a king of heart

b. a queen of spades

c. an ace of flower

d. an ace of diamond​

Solution:

In a standard deck of 52 cards.

Total number of cards = 52

13 cards of each suit (heart, diamond, club, spade).

13 cards are Ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, King.

a. We need to find the probability of getting a king of heart.

Number of king of heart = 1

P(\text{a king of heart})=\dfrac{\text{Number of king of heart}}{\text{Total cards}}

P(\text{a king of heart})=\dfrac{1}{52}

b. We need to find the probability of getting a queen of spades.

Number of queen of spades = 1

P(\text{a queen of spades})=\dfrac{\text{Number of queen of spades}}{\text{Total cards}}

P(\text{a queen of spades})=\dfrac{1}{52}

c. We need to find the probability of getting an ace of flower (spades).

Number of ace of flower = 1

P(\text{an ace of flower})=\dfrac{\text{Number of ace of flower}}{\text{Total cards}}

P(\text{an ace of flower})=\dfrac{1}{52}

d. We need to find the probability of getting an ace of diamond​.

Number of ace of diamond​ = 1

P(\text{an ace of diamond​})=\dfrac{\text{Number of ace of diamond​}}{\text{Total cards}}

P(\text{an ace of diamond​})=\dfrac{1}{52}

Therefore, the required probabilities for each parts are:

(a) \dfrac{1}{52}

(b) \dfrac{1}{52}

(c) \dfrac{1}{52}

(d) \dfrac{1}{52}

4 0
3 years ago
14. A delivery firm uses one fleet of trucks on daily routes of 8 h. A second fleet, with five more trucks than the first, is us
Sloan [31]

Answer:

.........................

5 0
3 years ago
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