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gladu [14]
3 years ago
14

Evaluate the following Piecewise Function. Please sturggeling

Mathematics
1 answer:
Anastaziya [24]3 years ago
3 0

Answer:

f(0)=4

f(6) = 8

Step-by-step explanation:

Given

The piece wise function

Solving (a): f(0)

To solve for f(0), we make use of:

f(x) = x + 4

Because: the inequality x < 5 satisfies x = 0

i.e: 0 < 5

So, we have:

f(x) = x + 4

f(0)=0 + 4

f(0)=4

Solving (b): f(6)

To solve for f(6), we make use of:

f(x) = 8

Because: the inequality 5 \le x < 7 satisfies x = 6

i.e: 5 \le 6 < 7

So, we have:

f(6) = 8

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Examine the following table, which represents some points on a line
Lady bird [3.3K]

Answer:

Option (b)

Step-by-step explanation:

Let the points represented by the given table lie on a line.

And the equation of the line is,

y = mx + b

Where m = slope of the line

b = y-intercept

Let the points lying on the line are (0, -2) and (3, -3)

Slope of the line 'm' = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m = \frac{-2-(-3)}{0-3}

m = \frac{-2+3}{0-3}

m = -\frac{1}{3}

y-intercept 'b' = (-2)

Equation of the line is,

y = -\frac{1}{3}x-2

This equation matches with equation given in option (b).

Option (b) will be the answer.

7 0
4 years ago
What is the area of this<br>irregular shape?<br>.6 ft<br>square feet<br>3 ft<br>8 ft<br>16 ft<br>​
Andrej [43]

Answer:

Step-by-step explanation:

area=16×8+1/2×3×6

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5 0
3 years ago
Triangle J K L is shown. Angle J K L is a right angle. An altitude is drawn from point K to point M on side L J to form a right
KiRa [710]

Answer:

3\sqrt{5}\ units

Step-by-step explanation:

<u>Theorem 1:</u> The height of right triangle drawn from the right angle to the hypotenuse divides the hypotenuse into two segments. The length of the altitude is the geometric mean of these two segments. Hence,

KM^2=ML\cdot MJ\\ \\6^2=ML\cdot 3\\ \\3ML=36\\ \\ML=12\ units

<u>Theorem 2:</u> In a right triangle, the altitude drawn from the right angle to the hypotenuse divides the hypotenuse into two segments. The length of each leg of the right triangle is the geometric mean of the lengths of the hypotenuse and the segment of the hypotenuse that is adjacent to the leg.

Thus,

KJ^2=MJ\cdot ML\\ \\KJ^2=3\cdot (3+12)\\ \\KJ^2=3\cdot 15\\ \\KJ^2=45\\ \\KJ=\sqrt{45}=3\sqrt{5}\ units

5 0
3 years ago
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Simplify the expression
25u

To find the what answer it is:
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7 0
4 years ago
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