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3 years ago

All of the following are bases except

Physics

2 answers:

boyakko [2]3 years ago

8 0

Answer:

Mila [183]3 years ago

6 0

HBr.
When you write the chemical formula of a compound
I. If there is H only it can be acid
II. If it has OH it is base

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Match the correct sentence together.

Brut [27]

I’m pretty sure you times them so 1 with A, 2 with e, 3 with C, and 4 with B

6 0

2 years ago

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Potential energy is due to_blank_?

nadezda [96]

gravity? I am not completly sure but this is my best guess

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3 years ago

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Two girls,(masses m1 and m2) are on roller skates and stand at rest, close to each other and face-to-face. Girl 1 pushes squarel

Arturiano [62]

Answer:

$\vec{v}_1 = -\frac{\vec{v}_2m_2}{m_1}$

Explanation:

The center of mass of the system (two girls) is constant, as the velocity of the center of mass of the system is also constant.

$\vec{v}_{cm} = \frac{m_1\vec{v}_1 + m_2\vec{v}_2}{m_1 + m_2}$

<u>The initial velocity of the system is zero, since both girls are at rest.</u> So the velocity of the total system at any point should be zero as well.

$0 = \frac{m_1\vec{v}_1 + m_2\vec{v}_2}{m_1 + m_2}\\\vec{v}_1 = -\frac{\vec{v}_2m_2}{m_1}$

This is true, because there is no friction between the girls and the ground. Otherwise, the velocity of the center of mass wouldn't be constant.

5 0

3 years ago

If an object on a horizontal frictionless surface is attached to a spring, displaced, and then released, it will oscillate. If i

sdas [7]

Answer: a. 5.115 b. 2pi c. i dont know

Explanation:

6 0

3 years ago

A person hears sound wave beast at 3000Hz at the temperature of 30 °C. What is the person's ear canal length? Please explain

Evgen [1.6K]

Answer:

The person's ear canal length is 2.91 cm.

Explanation:

Given that,

Frequency = 3000 Hz

Temperature = 30°C

We need to calculate the speed

Using equation of sound wave with temperature

[texs]v(t)=331+0.6\times T[/tex]

Put the value of T

$v(t)=331+0.6\times30^{\circ}\ C$

$v(t)=349\ m/s$

We need to calculate the length

Using formula of closed organ pipe

$f=\dfrac{v}{4L}$

$L=\dfrac{v}{4f}$

Where, L = length

v = velocity

f = frequency

Put the value into the formula

$L=\dfrac{349}{4\times3000}$

$L=0.0291\ m$

$L=2.91\times10^{-2}\ m$

$L=2.91\ cm$

Hence, The person's ear canal length is 2.91 cm.

4 0

4 years ago