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3 years ago

Suponga que usted pone en contacto 2 cuerpos, uno con carga +6 y otro con carga -8. ¿Con qué carga queda cada uno al final?

Physics

1 answer:

soldi70 [24.7K]3 years ago

4 0

What is the question?

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What is the repulsive force between two pith balls that are 8.00 cm apart and have equal charges of – 30.0 nC?

Nastasia [14]

Answer:

$F=1.26*10^{-3}N$

Explanation:

Assuming the pith balls as point charges, we can calculate the repulsive force between them, using Coulomb's law:

$F=\frac{kq_1q_2}{d^2}$

We observe that the magnitude of the electric force is directly proportional to the product of the magnitude of both signed charges( $q_1,q_2$ ) and inversely proportional to the square of the distance(d) that separates them.

Replacing the given values, where k is the Coulomb constant:

$F=\frac{8.99*10^{9}\frac{N\cdot m^2}{C^2}(-30*10^{-9}C)(-30*10^{-9}C)}{(8*10^{-2}m)^2}\\F=1.26*10^{-3}N$

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3 years ago

Divers in Acapulco dive from a cliff that is 65 m high. If the rocks

Ghella [55]

Answer:

did you have the same answer to get the best

6 0

2 years ago

A wooden piece is made in different shapes take length (l) = radius (r) = 2m Calculate its volume as a:

In-s [12.5K]

This question deals with the volume of different shapes.

a) volume of the sphere is "33.51 m³".

b) volume of the cylinder is "25.13 m³".

The volume of a sphere is given by the following formula:

$Volume = \frac{4}{3}\pi r^3\\\\Volume = \frac{4}{3}\pi (2\ m)^3$

Volume = 33.51 m³

The volume of a cylinder is given by the following formula:

$Volume = \pi r^2l\\\\Volume =\pi (2\ m)^2(2\ m)$

Volume = 25.13 m³

Learn more about volume here:

brainly.com/question/16686115?referrer=searchResults

The attached picture shows the formulae of the volume of different shapes.

7 0

3 years ago

YAHOO ANSWERSA 1260 kg car moving south at 12.9 m/s collides with a 2430 kg car moving north. The cars stick together and move a

Fofino [41]

Explanation:

Below is an attachment containing the solution.

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3 years ago

A train goes up a hill with a 15º incline. If the train has constant speed of 22 m/s, what are the vertical and horizontal compo

Kobotan [32]

Any two-dimensional vector in cartesian (x,y) coordinates can be broken down into individual horizontal and vertical components using trigonometry. If a train goes up a hill with 15 degree incline at a speed of 22 m/s, the horizontal component is 22cos(15)=21.3 m/s and the vertical component is 22sin(15)=5.5 m/s.

8 0

3 years ago