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Vera_Pavlovna [14]
3 years ago
10

Insert XXX to output the student's ID. public class Student { private double myGPA; private int myID; public getID) { return myI

D; public static void main(String [] args) { Student s = new Studento; XXX System.out.println("Student ID: "); System.out.println("Student ID:" + getID()); System.out.println("Student ID:" + s.getId()); System.out.println("Student ID:" + student.getID()); A static main() _ has direct access to class instance members can declare and create objects can call instance methods without an object O can not be included within a programmer-defined class What is stored in score1, score2, and grade? Integer scorel = 72; int score2 = 85; Character grade = 'C'; obj reference, 85, obj reference 72,85, obj reference, obj reference, obj reference obj reference, obj reference, Which is true? Instances of programmer-defined objects are immutable Contents of a Double instance can be modified after initialization An instance of String stores data rather than an object reference Reference variables store memory locations
Computers and Technology
1 answer:
Aleonysh [2.5K]3 years ago
7 0

Answer:

Explanation:

The question above is missing many details and are actually various questions in one. I will answer each one seperately below...

A. The piece of code to get the ID in this code snippet that needs to replace XXX would be the following ... System.out.println("Student ID: " + s.getID());

B. A static main() can declare and create objects. Once these objects are created their instance methods can then be called.

C. Integer score1 = 72;

    int score2 = 85;

    Character grade = 'C';

     In the above code snippet, the information stored in score1, score2, and grade are the following... obj reference, 85, obj reference. This is becasue both Integer and Character are classes and the values being passed to their variables are referencing that object class, while score2 is a primitive type of int and is therefore simply a number.

D. The statement that is true is ... Contents of a Double instance can be modified after initialization. Objects can be modified by calling its setter methods after initializing it.

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Create a list of strings based on a list of numbers The rules:_______
Delicious77 [7]

Answer:

listNumbers = [34,56,23,56,78,89,98,45,34,33,25,26,67,78]

listString = [ ]

for i in range(14):

   if listNumbers[i]%2!=0 and listNumbers[i]%5==0:

       listString.append("five odd")

   elif listNumbers[i]%5==0 and listNumbers[i]%2==0:

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   elif listNumbers[i]%2==0:

       listString.append("even")

   elif listNumbers[i]%2!=0:

       listString.append("odd")

print(listNumbers)

print(listString)

Explanation:

In python programming language;

  1. Create two lists
  2. The first is a list of numbers and initialize it with random values: listNumbers = [34,56,23,56,78,89,98,45,34,33,25,26,67,78]
  3. The second list is empty and will hold the string values listString = [ ]
  4. Use a for loop to iterate over all the elementts in the list of numbers
  5. Use the modulo operator (%) to chech for multiples of particular numbers as stipulated by the question
  6. Use combination of if/elif statements for each condition
  7. Use the .append method to add the elements into the list of strings
  8. finially output both lists

See attached code and output

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a

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just gesing

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what is the largest possible number of internal nodes in a redblack tree with black height k? what is the smallest possiblenumbe
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Answer:

A Red Black Tree is a type of self-balancing(BST) in this tree ,each node is red or black colored. The red black tree meets all the properties of the binary search tree, but some additional properties have been added to a Red Black Tree.

A Red-Black tree's height is O(Logn) where (n is the tree's amount of nodes).

In a red-black tree with black height k

The maximum number of internal nodes is 2^{2k} -1.

The smallest possible number is 2^{k} -1.

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