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Pavlova-9 [17]
3 years ago
7

When 1-methylcyclopentene undergoes acid catalyzed hydration, the major product formed is 1-methylcyclopentanol. What change(s)

in the reactants would result in 2-methylcyclopentanol being the major product
Chemistry
1 answer:
alina1380 [7]3 years ago
5 0

Answer:

Conversion of 1-methyl cyclopentene to 2-methyl cyclopentanol.

Explanation:

When alkenes react with diborane followed by the reaction with hydrogen peroxide and NaOH then the least substituted carbon in the double bond will be substituted.

The formation of 2-methyl cyclopentanol from 1-methyl cyclopentene is shown below:

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The freezing point of benzene C6H6 is 5.50°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in benzene is DDT . H
Vlad1618 [11]

Answer: 0.028 grams

Explanation:

Depression in freezing point :

Formula used for lowering in freezing point is,

\Delta T_f=k_f\times m

or,

\Delta T_f=k_f\times \frac{\text{ Mass of solute in g}\times 1000}{\text {Molar mass of solute}\times \text{ Mass of solvent in g}}

where,

\Delta T_f = change in freezing point

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m = molality

Putting in the values we get:

0.400^0C=5.12\times \frac{\text{ Mass of solute in g}\times 1000}{354.5\times 209.0}

{\text{ Mass of solute in g}}=0.028g

0.028 grams of DDT (solute) must be dissolved in 209.0 grams of benzene to reduce the freezing point by 0.400°C.

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how many mL of a 3.5 M sodium hydroxide will be needed to neutralize 15mL of a 4.3 M hydrochloric acid solution?
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Step 1 : write a valanced equation..
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Stem 3 : use mole ratio....
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Step 4 :
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