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Kobotan [32]
3 years ago
8

Predict the density of acetylene gas (C2H2) at 0.910 atm and 20oC.

Chemistry
1 answer:
zhuklara [117]3 years ago
6 0

Answer:

d = 0.98 g/L

Explanation:

Given data:

Density of acetylene = ?

Pressure = 0.910 atm

Temperature = 20°C (20+273 = 293 K)

Solution:

Formula:

PM = dRT

R = general gas constant = 0.0821 atm.L/mol.K

M = molecular mass = 26.04 g/mol

0.910 atm × 26.04 g/mol = d × 0.0821 atm.L/mol.K×293 K

23.7  atm.g/mol = d × 24.1 atm.L/mol

d = 23.7  atm.g/mol / 24.1 atm.L/mol

d = 0.98 g/L

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FinnZ [79.3K]

Answer:

2.9 g of water are produced by 9.6 g of ammonium perchlorate

<em>Note: The question is incomplete. The complete question is given below:</em>

<em>Ammonium perchlorate (NH₄ClO₄) is the solid rocket fuel used by the U.S. Space Shuttle. It reacts with itself to produce nitrogen gas (N₂) , chlorine gas (Cl₂), oxygen gas (O₂), water (H₂O) , and a great deal of energy. What mass of water is produced by the reaction of 9.6 g of ammonium perchlorate? Be sure your answer has the correct number of significant digits.</em>

Explanation:

The reaction of ammonium perchlorate (NH₄ClO₄) to produce nitrogen gas (N₂) , chlorine gas (Cl₂), oxygen gas (O₂), water (H₂O) is shown in the balanced chemical equation given below:

2 NH₄ClO₄ →  N₂ +  Cl₂ + 2 O₂ + 4 H₂O

From the equation, 2 moles of ammonium perchlorate produces 4 moles of water, i.e. mole ratio of NH₄ClO₄ to H₂O = 2 : 4 = 1 : 2

molar mass of ammonium perchlorate, NH₄ClO₄ = (14 + 4 * 1 + 35.5 +16 * 4) = 117.5

molar mass of water,  H₂O = (2 * 1 + 16) = 18.0 g

mass of water produced = moles of ammonium perchlorate * 2 * molar mass of water

moles of perchlorate = mass / molar mass = 9.6/117.5

mass of water produced = 9.6/117.5 * 2 * 18.0 g  = 2.94 g of water

Therefore, 2.9 g of water are produced by 9.6 g of ammonium perchlorate

6 0
3 years ago
What is the subscript present in NaCl?
jonny [76]

Answer:

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Explanation:

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4 years ago
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Nata [24]

Answer:

1. How do metals and non-metals react with acids?

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6 0
3 years ago
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If the δh°soln of hno3 is –33.3 kj/mol, then how much heat is evolved by dissolving 0.150 mol hno3 in 100.0 ml of water?
Leto [7]
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Explanation:

1) The heat evolved during the reation is proportional to the number of moles dissolved.

2) Proportionality = ratio is constant

<span>3) δh°soln of HNO3 is –33.3 kJ/mol => ratio 1

                  -33.3 kJ
ratio 1 = ---------------------
                 1 mol HNO3

4) ratio 2

        x
--------------
0.150 mol     
</span>
5) proportion

ratio 1 = ratio 2

        x                -33.3 kJ
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0.150 mol              1 mol

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