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3 years ago

Under ordinary conditions of temperature and pressure, the particles in a gas are

1 answer:

4 0

<span>In normal conditions gas particles remain very distant from each other. They rarely collide and are stable. When temperature increases the gas particles begin to move faster and collide more, reducing the distance. When pressure increases the gas particles also pick up kinetic speed and are also closer to each other.</span>

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1/4 checkpoint

DochEvi [55]

Answer:

here's the answers

Explanation:

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2 years ago

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A(n) _____ is a region where fresh water and salt water mix.

Airida [17]

It is called an estuary.

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3 years ago

Which of the following represents the smallest mass? I.) 23 cg II.) 2.3 x 10-3 μg III.) 0.23 mg IV.) 0.23 g V.) 2.3 x 10-2 kg

jenyasd209 [6]

The smallest mass among the choices is Choice (ii):2.3 x 10-3 μg

This is so because, the prefix μ signifies a factor of 10^-6.

For choice I:

23 cg means 23 centigrams

In essence = 0.23grams

For choice II:

2.3 × 10-3 μg means 2.3 × 10-9 grams

For choice III:

0.23 mg means 0.23 × 10-3 grams

For choice IV:

0.23 grams simply means 0.23grams

For choice V:

2.3 × 10-2 kg means 23 grams

Ultimately, Choice II represents the smallest mass.

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brainly.com/question/17192728

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1 year ago

The diagram below shows the energy conversions of the Krebs cycle, which is part of cellular respiration. The U-shaped

Jobisdone [24]

The answer to your problem is B

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2 years ago

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At a birthday pool party, the temperature is 28.50°C and the atmospheric pressure is 755.4 mmHg. One of the decoration helium ba

Iteru [2.4K]

Answer:

The volume of the balloon will be 5.11L

Explanation:

An excersise to solve with the Ideal Gases Law

First of all, let's convert the pressure in mmHg to atm

1 atm = 760 mmHg

760 mmHg ___ 1 atm

755.4 mmHg ____ (755.4 / 760) = 0.993 atm

922.3 mmHg ____ ( 922.3 / 760) = 1.214 atm

T° in K = 273 + °C

28.5 °C +273 = 301.5K

26.35°C + 273= 299.35K

P . V = n . R .T

First situation: 0.993atm . 6.25L = n . 0.082 . 301.5K

(0.993atm . 6.25L) / 0.082 . 301.5 = n

0.251 moles = n

Second situation:

1.214 atm . V = 0.251 moles . 0.082 . 301.5K

V = (0.251 moles . 0.082 . 301.5K) / 1.214 atm

V = 5.11L

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2 years ago

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