All categories

4 years ago

Find the variance of the given data rounded to the nearest hundredth 3,4,5,7,10,12,15

Mathematics

1 answer:

True [87]4 years ago

4 0

Answer:

(3 + 4 + 5 + 7 + 10 + 12 + 15)/7 = 8

(3^2 + 4^2 + 5^2 + 7^2 + 10^2 + 12^2 + 15^2)/7 - 8^2 = 17.14285714

You might be interested in

9. Which of the following do you need to know to determine the surface area and volume of a sphere?

Alexxx [7]

Answer:

A: radius of the sphere

Step-by-step explanation:

The formula for surface area is A = 4πr^2

With r being the radius and A the surface area.

For volume it is

V= (4/3)πr^3

6 0

3 years ago

What is the measure of the angle x?

navik [9.2K]

AOB = 2 . x
2x = 60°
x = 30°

4 0

3 years ago

Draw a right triangle with side lengths of 3, 4, and 5 units. and answer the problem please :')

11111nata11111 [884]

Answer:

Image below

Step-by-step explanation:

Given: Side lengths of a right triangle 3,4 and 5 units.

To draw: A right triangle with the given side length.

Solution:

We know, in a right angle triangle hypotenuse is the longest side and satisfying Pythagoras theorem.

From the given side length,

Hypotenuse = 5 unit

We can take any of the base and perpendicular.

Let, Base = 3 unit

Perpendicular = 4 unit.

It a right-angle triangle with a hypotenuse 5 unit.

Now we draw a right angle triangle taking in the first 3 base and 4 perpendicular and second 3 perpendicular and 4 bases.

8 0

2 years ago

Read 2 more answers

Which statement is sometimes true will give brainlist if righ and 10 extra points

arlik [135]

A rectangle is a square.

4 0

3 years ago

Read 2 more answers

Number 2 I need help on how to solve it

Hunter-Best [27]

Let's simplify the following expression:

$\text{ }\frac{\text{ \lparen2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{\text{ 6x}^5\text{y}^{-4}\text{z}^{-5}}{\text{ \lparen2x}^6\text{y}^3\text{z}^{-3})^2}$

We get,

$\text{ }\frac{(\text{2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{6x^5y^{-4}z^{-5}}{(2x^6y^3z^{-3})^2}$ $\text{ }\frac{(2x^4-y^6z^{-4})^2(6x^5y^{-4}z^{-5})}{(2x^2z^3)(2x^6y^3z^{-3})^2}$ $\text{ }\frac{(4x^8\text{ - 4x}^4y^6z^{-4}\text{ + y}^{12}z^{-8})(6x^5y^{-4}z^{-5})}{(2x^2z^3)(4x^{12}y^6z^{-6})}$ $\text{ }\frac{24x^{13}y^{-4}z^{-5}\text{ - 24x}^9y^2z^{-9}\text{ + 6x}^5y^8z^{-13}}{8x^{14}y^6z^{-3}}$

4 0

1 year ago