You use the Pythagorean theorem which is a^2+b^2=c^2
So....
.8^2+.6^2=c^2
.64+.36=c^2
1=c^2
1=c becaaue the square root of one is one
Angle B. Is 63 and Angle F. Is 59
Note that (a+b)^2 = a^2 + 2ab + b^2.
Therefore,
b^x (b^x )^2
<span>(2a^x +1/2 b^x)^2 becomes (2a^x)^2 + 2(2a^x)(-------- ) + ------------
2 4
LCD is 4. Thus, we have
4 [ (2a^(2x) ] + 8</span>a^x*b^x + b^(2x)
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