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3 years ago

Which of the following graphs shows a linear function

Mathematics

2 answers:

Mazyrski [523]3 years ago

7 0

The answer is definitely B

Karolina [17]3 years ago

5 0

Answer:

<u>B and C</u>

Step-by-step explanation: A linear function is a first grade polinomial function, that means every rect line.

The opcion B is a function like this ⇒ y(x)=x*a, a=constant.

The opcion C is a function like this ⇒ y(x)=/x/*a, a=constant.

Both questions are linearfunction

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3 times a number is 54 less than the square of that number. Find the negative solution.

son4ous [18]

Answer:

-6

Step-by-step explanation:

3n = n² - 54

n² - 3n - 54 = 0

n² - 9n + 6n - 54 = 0

n(n - 9) + 6(n - 9) = 0

(n - 9)(n + 6) = 0

n = 9 , -6

5 0

3 years ago

Hello, if you’re feeling generous today please lend a hand!! thank you

andrew11 [14]

Answer:

$x \leqslant 2$

Step-by-step explanation:

The point is shaded which means its is equal to and since the arrow goes to the left it is less than. Therefore x is less than or equal to 2

3 0

3 years ago

the diameters of Douglas firs grown at a Christmas tree farm are normally distributed with a mean of 4 inches and a standard dev

aksik [14]

Answer:

Proportion of the trees will have diameters between 2 and 6 inches = 0.8164

Step-by-step explanation:

Given -

Mean $(\nu )$ = 4

Standard deviation $(\sigma )$ = 1.5

Let X be the diameter of tree

proportion of the trees will have diameters between 2 and 6 inches =

$P(2< X< 6)$ = $P(\frac{2 - 4 }{1.5}< \frac{X - \nu }{\sigma}< \frac{6 - 4 }{1.5})$

= $P(\frac{-2 }{1.5}< Z< \frac{2 }{1.5})$ Put [ $Z = \frac{X - \nu }{\sigma}$ ]

= $P(-1.33< Z< 1.33)$

= $(Z< 1.33) - (Z< -1.33)$

= .9082 - .0918

= 0.8164

6 0

3 years ago

Determine whether the improper integral converges or diverges, and find the value of each that converges.

Ksju [112]

Answer:converge at $I=\frac{1}{3}$

Step-by-step explanation:

Given

Improper Integral I is given as

$I=\int^{\infty}_{3}\frac{1}{x^2}dx$

integration of $\frac{1}{x^2}$ is - $\frac{1}{x}$

$I=\left [ -\frac{1}{x}\right ]^{\infty}_3$

substituting value

$I=-\left [ \frac{1}{\infty }-\frac{1}{3}\right ]$

$I=-\left [ 0-\frac{1}{3}\right ]$

$I=\frac{1}{3}$

so the value of integral converges at $\frac{1}{3}$

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3 years ago

You by x packs of pencils, twice as many packs of erasers, and three times as many rolls of tape. Write an expression in the sim

ra1l [238]

Answer- since you are buying x packs of pencils, 2x packs of erasers, and 3x rolls of tape, you would be buying a total of 6x items.

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3 years ago