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laiz [17]
3 years ago
12

When 5.0 moles of butane react completely?

Chemistry
1 answer:
Korolek [52]3 years ago
7 0

Moles of Carbondioxide-CO₂ produced = 20 moles

<h3>Further explanation</h3>

The combustion of hydrocarbons with excess oxygen will produce carbon dioxide and water(CO₂+H₂O), whereas if there is not much oxygen, carbon monoxide and water(CO+H₂O) will be obtained.

The reaction coefficient in a chemical equation shows the mole ratio of the reacting compounds

Reaction (combustion of butane) :

<em>2C₄H₁₀+13O₂⇒8CO₂+10H₂O</em>

Butane reacts completely, then Butane is the limiting reactant and oxygen as the excess reactant, so the moles of Carbon dioxide are based on the butane moles as the limiting reactant.

moles of butane - C₄H₁₀ = 5 moles

From the reaction, the mol ratio of C₄H₁₀ and CO₂ : 2 : 8, so mol CO₂ :

\tt \dfrac{8}{2}\times 5~moles=20~moles

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Step 1: Data given

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Step 4: Calculate moles NaBH4

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Step 5: Calculate limiting reactant

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NaBH4 is the limiting reactant. It will completely be consumed ( 0.00397 moles).

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For 0.00397 of C14H10O3 we need 0.00397 mol of NaBH4 to produce 0.00397 mol of C7H8O

Step 7: Calculate mass of C7H8O

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