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3 years ago

Which equation represents an oxidation-reduction reaction?

1 answer:

3 0

In an oxidation-reduction reaction there is an exchange of electrons.

The exchange of electrons implies change in the oxidation states: at least one element increases its oxidation number while other reduces it.

By simple ispection you can predict that in the equation b. there is a change in oxidation states of Cl and Mn.

Now you can check it:

Equation 4H Cl + Mn O2 -> Mn Cl2 + 2H2 O + Cl2

oxidation sates 1+ 1- 4+ 2- 2+ 1- 1+ 2- 0

The oxidation state of Cl in HCl is 1- and it changed to 0 in Cl2

The oxidation state of Mn in MnO2 is 4+ and it changed to 2+ in MnCl2

Answer b.

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Be sure to answer all parts. Carbon dioxide (CO2) is the gas that is mainly responsible for global warming (the greenhouse effec

Elena L [17]

Answer:

1.60x10⁶ billions of g of CO₂

Explanation:

Let's calculate the production of CO₂ by a single human in a day. The molar mass of glucose is 180.156 g/mol and CO₂ is 44.01 g/mol. By the stoichiometry of the reaction:

1 mol of C₆H₁₂O₆ -------------------------- 6 moles of CO₂

Transforming for mass multiplying the number of moles by the molar mass:

180.156 g of C₆H₁₂O₆ ----------------- 264.06 g of CO₂

4.59x10² g ---------------- x

By a simple direct three rule:

180.156x = 121203.54

x = 672.77 g of CO₂ per day per human

So, in a year, 6.50 billion of human produce:

672.77 * 365 * 6.50 billion = 1.60x10⁶ billions of g of CO₂

5 0

2 years ago

Geologists use the Law of Superposition to date rock layers. However, the Earth's

Allisa [31]

The answer is d faults

4 0

2 years ago

How many moles is 1.50x10^23 molecules of NH3?

S_A_V [24]

The number of moles that are 1.50 x10^23 molecules of NH3 are

=0.249 moles

<u><em> calculation</em></u>

The number of moles is calculated using Avogadro's law constant

that is According to Avogadro's law

1 moles of a substance = 6.02 x10^23 molecules

? moles = 1.50 x10^23 molecules

by cross multiplication

= [( 1.50 x 10^23 molecules x 1 moles) / (6.02 x10^23)] = 0.249 moles

8 0

3 years ago

Read 2 more answers

Does SO3 2- show delocalized bonding

Veseljchak [2.6K]

Answer:

YES

Explanation:

SO3 2-DOES show delocalized bonding

delocalized bonding occurs when there is a resonance structure and the electronic bonds are a delocalised "cloud" around the species

The resonance effect of the sulfite sructures ithe folowing link:

https://www.chemistryscl.com/general/lewis-resonance-structure-of-SO32-/index.php

7 0

2 years ago

In the hypothetical reaction below, substance A is consumed at a rate of 2.0 mol/L·s. If this reaction is at dynamic equilibrium

ozzi

Answer : The correct answer for rate of consumption of B = $2.0 \frac{mol}{L*s}$

Dynamic equilibrium :

Dynamic equilibrium is state of equilibrium where reactants convert to product and product converts to reactant at equal and constant rate . The concentration may not be same but rate will be same .

This occurs when reaction is reversible type .

The hypothetical reaction is :

A ↔ B where ↔ represents reversible reaction

Rate of consumption of A is given as :

$R(a) = k * \frac{d[A]}{dt}$

Where . R(a) = rate of consumption of A

k = rate constant

[A] = concentration of A

t= time

Rate for consumption of B =

$R (b)= k * \frac{d[B]}{dt}$

R(b) = rate of consumption of B , [B] is concentration of B

Since the reaction is at dynamic equilibrium , so :

Rate of consumption of A = rate of consumption of B

Given : rate of consumption of A = $2.0 \frac{mol}{L*s}$

Hence rate of consumption of B = $2.0 \frac{mol}{L*s}$

6 0

3 years ago

Read 2 more answers