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Ganezh [65]
2 years ago
7

What is 16 divided by 845?

Mathematics
2 answers:
KATRIN_1 [288]2 years ago
5 0

Answer:

0.1882352941 or 16/845 as a fraction in its simplest form

Step-by-step explanation:

You can use long division or use a calculator. If you need help figuring out long division there are some great videos on You-Tube

Korolek [52]2 years ago
4 0

Answer:

0.01893491124

Step-by-step explanation:

If you meant 845 divided by 16 then the answer is 52.8125.

Please tell me if this helped you out

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Answer:

Happybday have a graet day miss uad

Step-by-step explanation:

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2 years ago
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Polygon B is a scaled copy of Polygon A using a scale factor of 5.
SVEN [57.7K]

Answer:

5times largerof apolygon

4 0
3 years ago
If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar
Oksana_A [137]

Answer:

n + 4 {n \choose 2} + 6 {n \choose 3} + 4 {n \choose 4} + {n \choose 5}

Step-by-step explanation:

Lets divide it in cases, then sum everything

Case (1): All 5 numbers are different

 In this case, the problem is reduced to count the number of subsets of cardinality 5 from a set of cardinality n. The order doesnt matter because once we have two different sets, we can order them descendently, and we obtain two different 5-tuples in decreasing order.

The total cardinality of this case therefore is the Combinatorial number of n with 5, in other words, the total amount of possibilities to pick 5 elements from a set of n.

{n \choose 5 } = \frac{n!}{5!(n-5)!}

Case (2): 4 numbers are different

We start this case similarly to the previous one, we count how many subsets of 4 elements we can form from a set of n elements. The answer is the combinatorial number of n with 4 {n \choose 4} .

We still have to localize the other element, that forcibly, is one of the four chosen. Therefore, the total amount of possibilities for this case is multiplied by those 4 options.

The total cardinality of this case is 4 * {n \choose 4} .

Case (3): 3 numbers are different

As we did before, we pick 3 elements from a set of n. The amount of possibilities is {n \choose 3} .

Then, we need to define the other 2 numbers. They can be the same number, in which case we have 3 possibilities, or they can be 2 different ones, in which case we have {3 \choose 2 } = 3  possibilities. Therefore, we have a total of 6 possibilities to define the other 2 numbers. That multiplies by 6 the total of cases for this part, giving a total of 6 * {n \choose 3}

Case (4): 2 numbers are different

We pick 2 numbers from a set of n, with a total of {n \choose 2}  possibilities. We have 4 options to define the other 3 numbers, they can all three of them be equal to the biggest number, there can be 2 equal to the biggest number and 1 to the smallest one, there can be 1 equal to the biggest number and 2 to the smallest one, and they can all three of them be equal to the smallest number.

The total amount of possibilities for this case is

4 * {n \choose 2}

Case (5): All numbers are the same

This is easy, he have as many possibilities as numbers the set has. In other words, n

Conclussion

By summing over all 5 cases, the total amount of possibilities to form 5-tuples of integers from 1 through n is

n + 4 {n \choose 2} + 6 {n \choose 3} + 4 {n \choose 4} + {n \choose 5}

I hope that works for you!

4 0
3 years ago
GEOMETRY. PLS HELP ASAP....<br> How can you verify Euler’s formula for this net of a cube?
Tomtit [17]
The above figure can be formed into a cube.

This is for any polyhedron that does not intersect itself. The Euler's formula states that the number of faces plus the number of vertices or corner points less the number of edges is always equal to 2.

Faces + Vertices - Edges = 2

A cube has 6 faces, 8 vertices, and 12 edges.

Euler's formula: 6 + 8 - 12 = 2 ⇒ 14 - 12 = 2 ⇒ 2 = 2


4 0
3 years ago
Select the correct answer,
stich3 [128]

Answer:

C.)

Step-by-step explanation:

every other customer at all the convenience stores in Springville that stock both brand A and brand B

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2 years ago
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