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2 years ago

Write the equation of the line that passes through the points (−7,0) and (6,−4).

Mathematics

1 answer:

Over [174]2 years ago

5 0

Answer:

y=-4/13x-28/13

Step-by-step explanation:

m=y2-y1/x2-x1

m=-4-0/6-(-7)

m=-4-0/6+7

m=-4/13

y-y1=m(x-x1)

y-0=-4/13(x-(-7))

y-0=-4/13x-28/13

y=-4/13x-28/13

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Mariana [72]

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3 years ago

Which statement describes the volume of the watering

lisabon 2012 [21]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

the eccentricity of a hyperbola is defined as e=c/a. find an equation with vertices (1,-3) and (-3,-3) and e=5/2

Ksivusya [100]

Answer:

$\frac{(x + 1 )^{2} }{4} - \frac{(y + 3 )^{2} }{21} = 1$ .

Step-by-step explanation:

If (α, β) are the coordinates of the center of the hyperbola, then its equation of the hyperbola is $\frac{(x - \alpha )^{2} }{a^{2} } - \frac{(y - \beta )^{2} }{b^{2} } = 1$ .

Now, the vertices of the hyperbola are given by (α ± a, β) ≡ (1,-3) and (-3,-3)

Hence, β = - 3 and α + a = 1 and α - a = -3

Now, solving those two equations of α and a we get,

2α = - 2, ⇒ α = -1 and

a = 1 - α = 2.

Now, eccentricity of the hyperbola is given by $b^{2} = a^{2}(e^{2} - 1) = 4[(\frac{5}{2} )^{2} -1] = 21$ {Since $e = \frac{5}{2}$ given}

Therefore, the equation of the given hyperbola will be

$\frac{(x + 1 )^{2} }{4} - \frac{(y + 3 )^{2} }{21} = 1$ . (Answer)

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2 years ago

Solve: 1/4x - 5 = 3/4x - 12

ivanzaharov [21]

The answer to the math problem it X=14 hope this helps

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3 years ago

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I know the answer but plz explain it. 5:3 × 6:2

stira [4]

5:3 x 6:2 can also be written as a fraction
5/3 x 6/2
Multiply across
30/6
Simplify
5/1
Rewrite
5:1 is your answer, or if your teacher does not want it simplified, 30:6

Hope I helped! :)

3 0

2 years ago