The greatest number of sets would be 20 with one girl and one boy in each.
Answer:
Your answer would be A and D hope this helps :)
Median = 5
Mean = 5.4444444444444
Mode: 3
Range = 9
Minimum = 1
Maximum = 10
How to find Median:
Arrange your numbers in numerical order. Then the second step is to have an odd number, divide by 2 and round up to get the position of the median number. The last step is to find the even number and if you have it, divide it by 2.
Answer: 5
Hope this helps.
Answer:
Lily babysit for <u>less than 4 hours</u>.
Step-by-step explanation:
Given:
Lucy spends in a week babysitting for 4 hours.
Lily spends seven-eighths of 4 hours.
Now, to find whether Lily babysit for more than 4 hours or less than that.
Number of hours Lucy babysit = 4 hours.
So, to get the hours Lily babysit:


<em>On simplifying we get:</em>

<u><em>Thus, Lily spends </em></u>
<u><em> for babysitting which is less than 4 hours.</em></u>
Therefore, Lily babysit for less than 4 hours.
Using the fundamental counting theorem, we have that:
- 648 different area codes are possible with this rule.
- There are 6,480,000,000 possible 10-digit phone numbers.
- The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.
The fundamental counting principle states that if there are p ways to do a thing, and q ways to do another thing, and these two things are independent, there are ways to do both things.
For the area code:
- 8 options for the first digit.
- 9 options for the second and third.
Thus:

648 different area codes are possible with this rule.
For the number of 10-digit phone numbers:
- 7 digits, each with 10 options.
- 648 different area codes.
Then

There are 6,480,000,000 possible 10-digit phone numbers.
The amount of possible phone numbers is greater than 400,000,000, thus, there are enough possible phone numbers.
A similar problem is given at brainly.com/question/24067651