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Answer:
B. ) x² + 4x + 3
Step-by-step explanation:
(f-g)(x) = f(x) - g(x) =
(2x²-5) - (x²-4x-8) =
2x² - x² + 4x + 8 - 5 =
x² + 4x + 3
Answer:
55 days
Step-by-step explanation:
Given
Jim ran 15 miles in 5 days
no. of miles ran in 5 days = 15 miles
dividing LHS and RHS by 5
no. of miles ran in 5/5(=1) days = 15/5 miles = 3 miles
no. of miles ran in 1 day = 3 miles
let the no. of days taken to run 165 miles be x ----A
No of miles ran in x days = x*no. of miles ran in 1 day = 3x miles
thus, From A
3x = 165
x = 165/3 = 55
Thus, it took 55 days for JIM to run 165 miles
Answer:
A. b(w) = 80w +30
B. input: weeks; output: flowers that bloomed
C. 2830
Step-by-step explanation:
<h3>Part A:</h3>
For f(s) = 2s +30, and s(w) = 40w, the composite function f(s(w)) is ...
b(w) = f(s(w)) = 2(40w) +30
b(w) = 80w +30 . . . . . . blooms over w weeks
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<h3>Part B:</h3>
The input units of f(s) are <em>seeds</em>. The output units are <em>flowers</em>.
The input units of s(w) are <em>weeks</em>. The output units are <em>seeds</em>.
Then the function b(w) above has input units of <em>weeks</em>, and output units of <em>flowers</em> (blooms).
__
<h3>Part C:</h3>
For 35 weeks, the number of flowers that bloomed is ...
b(35) = 80(35) +30 = 2830 . . . . flowers bloomed over 35 weeks
1.
A. (49-8)*2-16, 41*2-16, 82-16, 66, yep
B. 49-8*-14, 49+112, 161, nope
C. 7^(-16)-16, (1/(7^16))-16, nope
D. 49-16-16, 17, nope
A is answer
2.
2((a+b)²-b)
2((7+1)²-1)
2((8)²-1)
2(64-1)
2(63)
126
C is answer
4.
none of the options give the answer
