![\qquad \tt \rightarrow \:Domain = [-9, -1]](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Crightarrow%20%5C%3ADomain%20%3D%20%5B-9%2C%20-1%5D)
![\qquad \tt \rightarrow \:Range = [-1 , 3]](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Crightarrow%20%5C%3ARange%20%3D%20%5B-1%20%2C%203%5D)
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Domain = All possible values of x for which f(x) is defined
[ generally the extension of function in x - direction ]
Range = All possible values of f(x)
[ generally the extension of function in y - direction ]
![\qquad \tt \rightarrow \: domain = [ - 9, -1]](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Crightarrow%20%5C%3A%20domain%20%3D%20%5B%20-%209%2C%20-1%5D)
![\qquad \tt \rightarrow \: range= [ -1,3]](https://tex.z-dn.net/?f=%5Cqquad%20%5Ctt%20%5Crightarrow%20%5C%3A%20range%3D%20%5B%20-1%2C3%5D)
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
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Step-by-step explanation:
Answer:
70 min
Step-by-step explanation:
If we take the hypothesis that by the end of the fifth day he had 5h20min drums practice then the remaining time to get to 7 hours practice time would be 1h40min.
Answer:
the initial height of ball when the player releases it
Step-by-step explanation:
A basketball player shoots a free throw in a game. The quadratic expression models the height of the ball, in feet, where t is the time, in seconds.
y= -16t^2 + 25t+7
Given equation is in the form of
y= -16x^2 + V t + h
Where V represents the initial velocity and h represents the initial height of the ball
Now we compare our equation with the general equation
We have 7 in the place of h
So , 7 is the initial height of the ball
Answer is 7 is the initial height of ball when the player releases it
X=1/2
Alternative: 0.5 or 2^-1
