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galina1969 [7]
3 years ago
8

Can you guys please help me solve this

Mathematics
1 answer:
Delicious77 [7]3 years ago
6 0

Answer:

it didnt load the picture, it doesnt show my guy

Step-by-step explanation:

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Does anyone know the answer for this? ​
sergey [27]

Answer:

The line shifts down 5 units

Step-by-step explanation:

6 0
3 years ago
I need 3 4 and 5 ill mark you brainiest
AysviL [449]

Answer:

3) x=4      4)x = 9     5) x=5

Step-by-step explanation:

3) first you have to find the inside of the angle. A straight line = 180*

180-(19x+3) = 177-19x

Than you add all the angles up to equal 180.

(177 - 19x) + (11x-2) + (9x+1) = 180

if you simplify this x = 4. You can check your answer by subbing in for x.

4)first you have to find the inside of the angle. A straight line = 180*

180- (17x-23) = 203-17x

Than add the sides up to equal 180. keep in mind there are 2 of the same angles.

(203-17x)+(7x+2)(2) = 180

Simplify

x=9

5) 180-151=29* this is the inner angle.

(11x-1)+(20x-3)+29=180

31x+25=180

x=5

6 0
4 years ago
Read 2 more answers
Suppose that the annual rainfall in Ferndale, California, is known to be normally distributed, with a mean of 35.5 inches and a
erastovalidia [21]

The average annual rainfall will be more than 40.6 inches in about 2.1 percent of the years.

<h3>What is the average annual rainfall?</h3>

Generally, the equation for the probability is mathematically given as

P( X < x) = p( Z < x - \mu / \sigma)

Therefore

P( X > x) = 0.021

P( X < x ) = 1 - 0.021\\\\\p( X < x) = 0.979

P( Z < x - \mu / \sigma) = 0.979

The z score for the probability of 0.979 is 2.034, according to the table of z values.

x - \mu / \sigma \\\\x= 2.034

In the given equation, replace the values of mu and sigma with their respective values, and then solve for x.

x - 35.5 / 2.5 \\x= 2.034

In conclusion, The average annual rainfall will be more than 40.6 inches in about 2.1 percent of the years.

Read more about average

brainly.com/question/24057012

#SPJ1

7 0
2 years ago
A manager records the repair cost for 4 randomly selected TVs. A sample mean of $88.46 and standard deviation of $17.20 are subs
WINSTONCH [101]

Answer:

a) The critical value is z = 2.575.

b) The 99% confidence interval for the mean repair cost for the TVs is ($66.31, $110.61).

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha. This is our critical value

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

a. Find the critical value that should be used in constructing the confidence interval.

The critical value is z = 2.575.

b. Construct the 99% confidence interval. Round your answer to two decimal places.

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample. So, in this problem

M = 2.575*\frac{17.20}{\sqrt{4}} = 22.15

The lower end of the interval is the mean subtracted by M. So it is 88.46 - 22.15 = $66.31

The upper end of the interval is the mean added to M. So it is 88.46 - 22.15 = $110.61

The 99% confidence interval for the mean repair cost for the TVs is ($66.31, $110.61).

5 0
3 years ago
Simplify 8√40 - 3√90​
Colt1911 [192]

Answer:

7√10

Step-by-step explanation:

8√40 - 3√90​

8√(2^2*2*5) - 3√(3^2*2*5)

16√10 -9√10

7√10

5 0
3 years ago
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