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TiliK225 [7]
3 years ago
7

Which type of bond will most likely be found in HBr given that the electronegativity of hydrogen is 2.20 and the electronegativi

ty of bromine is 2.96?
an ionic bond
a metallic bond
a polar covalent bond
a nonpolar covalent bond
Chemistry
2 answers:
Anon25 [30]3 years ago
3 0

Answer:

C. A polar covalent bond

Artemon [7]3 years ago
3 0

Answer:

C. a polar covalent bond

Explanation:

I just did the quiz and got a 100% EDG21

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Write the molecular formula for a compound with the possible elements c, h, n and o that exhibits a molecular ion at m+ = 91.043
timama [110]
We are given the mass spectrum data for this compound which has a molecular ion peak of m+ = 91.043 m/z. When we have an m+ peak that is an odd number, that suggests that there are an odd number of nitrogens, in this case we'll assume 1 nitrogen atom to start. Nitrogen has a mass of 14 so we will substract that from our initial value.

91- 14 (1N) = 77 m/z

We are also told that there are carbon, hydrogens and oxygens present, so we will assume there is at least one oxygen which has a mass of 16 and subtract that value.

77 - 16 (1 O) = 61 m/z

Now we will try to get as close as possible to the remaining mass with carbons that has a mass of 12, and fill the remaining mass with hydrogens that have a mass of 1.

61 / 12 = 5
5 x 12 = 60

61 - 60 (5 C) = 1 m/z and this leaves us with 1 H.

The current formula would be C₅HON, but this structure is impossible since we do not have enough hydrogens to satisfy the carbons. So we can try to use 4 carbons instead and fill the rest with hydrogens.

4 x 12 = 48
61 - 48 (4 C) = 13 m/z and this leaves us with 13 H.

The current formula would be C₄H₁₃ON. The most hydrogens we can have in a compound is 2n+2 where n is the number of carbons. So with 4 carbons the most hydrogens we could have is 10. Therefore, our formula has too many hydrogens and also cannot work. So we cannot make up the remaining mass with carbons and hydrogens, therefore, we should add another oxygen before working with carbons and hydrogens.

61 - 16 (1 O) = 45 m/z
45/ 12 = 3.75
3 x 12 = 36

45 - 36 (3 C) = 9 m/z which gives us 9 hydrogens left.

The current formula is now C₃H₉O₂N. To test if this formula works we can calculate the double bond equivalents (DBE), also known as degrees of unsaturation.
DBE = C - H/2 + N/2 + 1 = 3 - (9/2) + (1/2) + 1 = 0

A value of 0 DBE tells us that there are no double bonds in this molecule but that the formula is a possibility so:

C₃H₉O₂N = 91 m/z
8 0
3 years ago
Chemists can use moles to calculate:
Dominik [7]

The moles are used to determine the atoms and molecules in a substance. It is used by chemists to determine the amount of reactants needed and products produced. Thus, option B is correct.

<h3>What are moles?</h3>

A mole is said to be defined as the estimation of the small entities like the atoms as that of the Avagadro's number 6.022 × 10²³. It defines the number of particles contained in a substance.

The moles of the substances are determined by the mass of the substance and its molar mass. The moles are given as,

Moles = mass ÷ molar mass

The moles give the estimation of the amount of the reactants needed to produce the products in a chemical reaction.

Therefore, option B. the moles tell the amount of the reactants required to produce the product.

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Calculate the values of ΔU, ΔH, and ΔS for the following process:
kykrilka [37]

The values of the changes are

ΔH = 46.44kJ

Δu =  43.34Kj

ΔS = 126.6 J/K

<h3>How to find change in H</h3>

= 1 mol + 75.3 (100 + 273) - 25 + 273 + 1 * 40.79

= 5.6475 + 40.79

= 46.44kJ

<h3>How to find change in S</h3>

1 mol + 75.3 x ln 373/298 + 1 mol x 40.79

= 0.1263

ΔS = 126.6 J/K

<h3>How to find the change in U</h3>

46.44 - 0.00831 * 373

= 43.34Kj

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