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vovangra [49]
4 years ago
14

Which example is a homogenous mixture of two or more pure substances? alcohol

Chemistry
1 answer:
il63 [147K]4 years ago
6 0

Answer:

Alcohol and water.

Explanation:

Alcohol and water is a homogenous mixture. because these two liquids are soluble, miscible in all composition. A homogenous mixture is a solution that has equal  composition of its components.

Irregular mixing of two liquid components have different refractive indexes. At a high temperature, it can become inhomogenous spontaneously.

A solution is a type of homogenous mixture which composed of two or more substances. In a mixture a solute is a substance, dissolves in other substance that is solvents like alcohol and water, alcohol is solute and water is a solvent.

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E ) The distribution coefficient , Ko ( Cether / C water ) , for an organic substance X at room temperature is 13. What relative
TiliK225 [7]

Answer:

Relative volume of ether to water that should be used for the extraction = 1.205

Explanation:

The extraction/distribution coefficient of an arbitrary solvent to water for a given substance is expressed as the mass concentration of the substance in the arbitrary solvent (C₁) divided by the mass concentration of the substance in water (C₂).

K = (C₁/C₂)

Let the initial mass of the organic substance X in water be 1 g (it could be any mass basically, it is just to select a right basis, since we are basically working with percentages here).

If 94% of the organic substance X is extracted by ether in a single extraction, 0.94 g ends up in ether and 0.06 g of the organic substance X that remains in water.

Let the volume of ether required be x mL.

Let the volume of water required be y mL.

Relative volume of ether to water that should be used for the extraction = (x/y)

Mass concentration of the organic substance X in ether = (0.94/x)

Mass concentration of organic substance X in water = (0.06/y)

The distribution coefficient , Ko (Cether / C water), for an organic substance X at room temperature is 13.

13 = (0.94/x) ÷ (0.06/y)

13 = (0.94/x) × (y/0.06)

13 = (15.667y/x)

(x/y) = (15.667/13) = 1.205

Hope this Helps!!!

4 0
3 years ago
Part A What are plate boundaries at which lithospheric plates that a) move toward each other, b) move past each other, and c) mo
Alex787 [66]

Answer:

a. Convergent boundary

b. Transform boundary

c. Divergent boundary

Explanation:

Convergent boundary are boundary where tectonic plates collide with each other. This kind of boundary might involve a collision between continental and oceanic plates, continental and continental plates and oceanic and oceanic plates. Generally, convergent boundary are regions for mountainous structures . Example of mountain formed through convergence are mountain Everest and Himalayas .

Transform boundary are boundary where tectonic plates move past each other . This kind of boundary is responsible for the creation of Extensive Fault like the San Andrea Fault.

Divergent boundary are boundary where tectonic plates move away from each other.  The diverging movements brings about oceanic ridges. The mid oceanic ridges is where magma rises to the surface to form a new crust. The up welling of this magma causes further separation of this plates.

The picture above illustrate convergent, divergent and transform boundary.

4 0
4 years ago
How to do dots and cross diagrams
Likurg_2 [28]

Answer:

Draw circles to represent the electron shell of each atom overlapping the circles where the atoms are bonded. Add dots to represent the outer electrons of one type of atom (H). Add crosses to represent the outer electrons of the other type of atom (Cl). Make sure the electrons are always in pairs.

6 0
3 years ago
If an element has more than one ionic charge, how is that piece of information represented in a chemical name?
Lostsunrise [7]
Usually with roman numerals, like iron (II) chromate
iron has a charge of 2
or manganese (IV) oxide, manganese has a charge of 4
(these are ionic compounds just to let you know)

3 0
3 years ago
g How many grams of beryllium are needed to produce "11.5" g of hydrogen gas?Be(s) + 2H 2 O(l) → Be(OH) 2 (aq) + H 2 (g)
slega [8]

Answer:

m_{Be}=51.3gBe

Explanation:

Hello,

In this case, with the given chemical reaction:

Be(s) + 2H_2 O(l) \rightarrow Be(OH)_ 2 (aq) + H _2 (g)

We can notice a 1:1 mole ratio between hydrogen gas and beryllium metal, therefore, beryllium requirement is computed as shown below:

m_{Be}=11.5gH_2*\frac{1molH_2}{2.02gH_2} *\frac{1molBe}{1molH_2} *\frac{9.01gBe}{1molBe}\\ \\m_{Be}=51.3gBe

Regards.

6 0
3 years ago
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