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Oksanka [162]
3 years ago
8

Two forces of 418 N. And 590 N. Act on an object the angle between the forces is 48° find the magnitude of the resultant and the

angle that it makes with the larger force
Mathematics
1 answer:
Schach [20]3 years ago
4 0

Answer:

Magnitude of the resultant force (Rf) = 923.5 N (Approx)

Step-by-step explanation:

Given:

Force f1 = 418 N

Force f2 = 590 N

Angle between the forces = 48°

Find:

Magnitude of the resultant force (Rf)

Computation:

Rf = \sqrt{f1^2+f2^2+2f1f2cos\theta} \\\\ Rf = \sqrt{418^2+590^2+2(418)(590)cos(48)}\\\ Rf = \sqrt{174,724+348,100+330,041.98} \\\\ Rf = \sqrt{852,865.98}\\\\ Rf = 923.5

Magnitude of the resultant force (Rf) = 923.5 N (Approx)

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kenny6666 [7]

Answer: 2929 π  inch

Step-by-step explanation:

Circumference is given by= 2πr

Here r= 1010 inches

So Tip of minute hand moves= 2π (1010inch)

                                                = 2020 π inch for an hour

Now it comes from 12 to 33 o'clock=  1.45 hour so,

Tip of minute hand moves= 2020 π inch  x 1.45

Tip of minute hand moves= 2929 π  inch

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Step-by-step explanation:

(x+5)^2 = 2( 5x-3)

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x^2-10x+25+6= 0

x^2-10x+31=0

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8 0
3 years ago
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-8 *-8 * -8 * -8 can be expressed as?
ZanzabumX [31]

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Step-by-step explanation:

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3 years ago
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Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round y
kupik [55]

Answer:

75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.

Step-by-step explanation:

The question is missing. It is as follows:

Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69  104  125  129  60  64

Assume that the population of x values has an approximately normal distribution.

Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)

75% Confidence Interval can be calculated using M±ME where

  • M is the sample mean weight of the wild mountain lions (\frac{69 +104 +125 +129+60 +64}{6} =91.8)
  • ME is the margin of error of the mean

And margin of error (ME) of the mean can be calculated using the formula

ME=\frac{t*s}{\sqrt{N} } where

  • t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
  • s is the standard deviation of the sample(31.4)
  • N is the sample size (6)

Thus, ME=\frac{1.30*31.4}{\sqrt{6} } ≈16.66

Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5

3 0
3 years ago
PLEASE HELP ME ASAP!!!!!!!!
Svetlanka [38]
Wouldn't it be B ??? Hope this is right:) can you take a look at mine??
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