All categories

2 years ago

Find the surface area of the above solid

Mathematics

1 answer:

vazorg [7]2 years ago

6 0

Answer:did u ever find the answer i need it

Step-by-step explanation:

You might be interested in

Find the sum of the measures of the interior angles of a polygon with 41 sides

Zolol [24]

Answer:

the formula is (n-2)180 degrees

so its 7020

8 0

2 years ago

Find the 9th term of the geometric sequence 5, -25, 125, ...

arlik [135]

Answer:

Step-by-step explanation:

a = 5

r = -5

n = 9

t_9 = a r^(n - 1)

t_9 = (-1)^n*5 (-5) ^ 8

t_9 = (-1)^9 * 5 * (-5) ^8

t_9 = -1 ( 1953125)

t_9 = - 1953125

6 0

2 years ago

Kansas has an area of 82,277 square miles.

dezoksy [38]

Answer:

75806

Step-by-step explanation:

82,277-6,471=75806

4 0

2 years ago

Read 2 more answers

Cot^2x/cscx-1=1+sinx/sinx

KATRIN_1 [288]

$\bf \textit{difference of squares}
\\\\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)
\\\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)\\\\
-------------------------------\\\\
\cfrac{cot^2(x)}{csc(x)-1}=\cfrac{1+sin(x)}{sin(x)}\impliedby \textit{let's do the left-hand-side}$

$\bf \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1}{sin(x)}-1}\implies \cfrac{\quad \frac{cos^2(x)}{sin^2(x)}\quad }{\frac{1-sin(x)}{sin(x)}}\implies \cfrac{cos^2(x)}{sin^2(x)}\cdot \cfrac{sin(x)}{1-sin(x)}
\\\\\\
\cfrac{cos^2(x)}{sin(x)}\cdot \cfrac{1}{1-sin(x)}\implies \cfrac{cos^2(x)}{sin(x)[1-sin(x)]}$

$\bf \cfrac{1-sin^2(x)}{sin(x)[1-sin(x)]}\implies \cfrac{1^2-sin^2(x)}{sin(x)[1-sin(x)]}
\\\\\\
\cfrac{\underline{[1-sin(x)]}~[1+sin(x)]}{sin(x)\underline{[1-sin(x)]}}\implies \cfrac{1+sin(x)}{sin(x)}$

5 0

2 years ago

Which set of angles are complementary in this diagram? Please help <3

SashulF [63]

9514 1404 393

Answer:

Step-by-step explanation:

Complementary angles total 90°. Here, 90° angle BCE is divided by ray CF into two complementary angles. They necessarily have a total of 90°.

∠ECF and ∠BCF

6 0

1 year ago