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Rzqust [24]
3 years ago
15

The quantity q varies inversely with the square of m and directly with the product of r and x. When q is 2.5, m is 4 and the pro

duct of r and x is 8. What is the constant of variation?
5/8
5/4
5
10
Mathematics
2 answers:
Usimov [2.4K]3 years ago
7 0

Answer:  Third option is correct.

Step-by-step explanation:

Since we have given that

The quantity q varies inversely with the square of m and directly with the product fo r and x.

According to question,

q=k\frac{rx}{m^2}\\\\\text{ where k denotes constant of variation}

Since q=2.5, m=4, rx=8,

So, we put the value of all of theses in our above relation:

q=k\frac{rx}{m^2}\\\\2.5=k\frac{8}{4^2}\\\\2.5=k\frac{8}{16}\\\\2.5=k\frac{1}{2}\\\\2.5\times 2=k\\\\5=k

Hence, Third option is correct.

Zolol [24]3 years ago
5 0
Q = k * (r*x)/m^2 ⇒ k = q*m^2 /(r*x)

k = 2.5 (4)^2 / 8 = 5

Answer: 5
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