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Rzqust [24]
3 years ago
15

The quantity q varies inversely with the square of m and directly with the product of r and x. When q is 2.5, m is 4 and the pro

duct of r and x is 8. What is the constant of variation?
5/8
5/4
5
10
Mathematics
2 answers:
Usimov [2.4K]3 years ago
7 0

Answer:  Third option is correct.

Step-by-step explanation:

Since we have given that

The quantity q varies inversely with the square of m and directly with the product fo r and x.

According to question,

q=k\frac{rx}{m^2}\\\\\text{ where k denotes constant of variation}

Since q=2.5, m=4, rx=8,

So, we put the value of all of theses in our above relation:

q=k\frac{rx}{m^2}\\\\2.5=k\frac{8}{4^2}\\\\2.5=k\frac{8}{16}\\\\2.5=k\frac{1}{2}\\\\2.5\times 2=k\\\\5=k

Hence, Third option is correct.

Zolol [24]3 years ago
5 0
Q = k * (r*x)/m^2 ⇒ k = q*m^2 /(r*x)

k = 2.5 (4)^2 / 8 = 5

Answer: 5
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Ur output value is f(x).....so to do this problem u need to sub in 2/3 for f(x) and solve for the input value which is x

f(x) = -1/3x + 7
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2 = -x + 21
2 - 21 = - x
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7 0
3 years ago
Read 2 more answers
1. The diameter of a sphere is 21.6 cm. The volume of the sphere is __
sveta [45]
Detailed Answers:

Volume of a Sphere (V) = 4/3 πr^3

1. Diameter (d) = 21.6 cm
Radius (r) = 21.6/2 = 10.8 cm

Therefore,
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= 4/3 * 22/7 * (10.8)^3
= 4/3 * 22/7 * 1259.712
= 88/21 * 1259.712
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Volume (V) = 5278.79 cm^3

2. Diameter (d) = 16 cm
Radius (r) = 16/2 = 8 cm

Therefore,
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= 4/3 * 22/7 * (8)^3
= 4/3 * 22/7 * 512
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Volume (V) = 2145.52 cm^3

3. Diameter (d) = 24 cm
Radius (r) = 24/2 = 12 cm

Therefore,
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4. Diameter (d) = 6 cm
Radius (r) = 6/2 = 3 cm

Therefore,
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6 0
1 year ago
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Paladinen [302]

Answer:

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Step-by-step explanation:

From the question, we have:

Sack\ 1: B, W

Sack\ 2: G, Y

Sack\ 3: S, R

Required

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The selection process is as follows:

Sack\ 1: B, W

Sack\ 1\ and\ Sack\ 2: B (G,Y); W(G,Y) -- i.e. we write sack 2 as a subset of 1

Sack\ 1, 2\ and\ 3: B (G(S,R),Y(S,R)); W(G(S,R),Y(S,R)) -- i.e. we write sack 3 as a subset of 2

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