Answer and Step-by-step explanation:
a.)x^2 and y^2 are always greater than zero.(assuming real x and y).
=>x^2<=x^2+y^2
=>|x|(x^2)<=|x|(x^2+y^2)
=>|x^3|<=|x|(x^2+y^2)
b. similarly, |y^3|<=|y|(x^2+y^2)
=>|f(x,y)|=|x^3+y^3|/(x^2+y^2)=|x|+|y|
c. let h is very small number (close to zero but positive)
lim (x,y)-> (0,0) f(x,y)=(x^3+y^3)/(x^2+y^2)
putting x=h and y=h and approaching h->0
lim h->0 f(h)=2h=0
There is another explanation attached below
Answer:
<u>Solving it mentally</u> :-
It says 25% × 44. When we have a percent, change it to decimal and solve which would be easy to do it mentally.
25% = 0.25
0.25 × 44 = 11 *Answer is bolded.*
<u>Solving it on paper</u> :-
I have attached a picture of me doing it on paper.
Hope this helps, thank you :) !!
Subtracting a value from the exponent shifts the graph to the right.
So if you subtract 3, the graph would shift 3 units to the right.
The answer is that y is equal to -3 and x is equal to 7
2x-y=17
-2(x-y)=10 )
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2x-y=17
-2x+2y=-20
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y=-3
x-y=10
x-(-3)=10
x+3=10
-3 -3
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x=7
Answer:
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Step-by-step explanation:
