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lawyer [7]
3 years ago
12

Write 4.48 as a mixed number in simplest form.

Mathematics
2 answers:
Gnom [1K]3 years ago
7 0

Answer:

4  12/25

Step-by-step explanation:

4.48 can be written as 4 48/100

Simplify

4 24/50

Simplify some more

4 12/25

Hope this helped :)

(Didn't you just ask this question?)

serg [7]3 years ago
3 0

Answer:

4 48/100 or 4 12/25

Step-by-step explanation:

the 48 in the hundredths place is obviously going to equal 48/100 and you can divide both the 48 and 100 by 4. 48÷4=12 100÷4=25

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3 years ago
10 A group of young men decided to raise sh 480 000 to start a business.. Before the actual payment was made, four of the member
stich3 [128]

A group of young men decided to raise Ksh.480000 to start a business. Before actual payment was made four members pulled out and each of the remaining had to pay an additional Ksh.20000. Write an expression in terms of P for.

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(ii) Contribution after withdrawal of four members.

(b) Form an equation in P and hence determine the number of initial members.

(c) Three men Kamau, James and Hassan shared Shs.480000 such that Kamau: James is 3: 2 and James: Hassan is 4: 2. Find how much each got.

3 0
2 years ago
Oatmeal is made by mixing 15 cups of hot water to 6 cups of oats.
skad [1K]

9514 1404 393

Answer:

  • 2/5 cups oats per cup water
  • 2.5 cups water per cup oats

Step-by-step explanation:

The denominator of the fraction is the unit you want 1 of.

  (6 cups oats)/(15 cups water) = (6/15) cups oats/(1 cup water)

  = (2/5 cups oats)/(1 cup water)

1 cup of water would need 2/5 cups of oats.

__

Obviously, the other ratio is the reciprocal of this.

  (1 cup water)/(2/5 cups oats) = (5/2 cups water)/(1 cup oats)

1 cup of oats would need 2.5 cups of water

7 0
3 years ago
You need to construct an open-top rectangular box with a square base that must hold a volume of exactly 475 cm3. The material fo
zepelin [54]

Answer:

The dimensions of the box are:

x =  8,93 cm       and     h  =   5,95 cm

C(min) =  850,69 cents

Step-by-step explanation:

The volume of the box is:

V = x²*h          where    x is the side of the square base  and h the height

then    h  =  V/ x²  ⇒    h = 475 / x²

The total cost of box C is:

C  = C₁  +  4*C₂      Where C₁  and C₂  are the costs of the base and one lateral side respectevily

Then cost C =  8*x²   + 4* 6*h*x

The cost C as a function of x is

C(x)  =  8*x²  + (24* 475 /x² )*x

C(x)  =  8*x²  +  11400/x

Tacking derivatives on both sides of the equation

C´(x)  =  16*x -  11400/x²

C´(x)  =  0     ⇒    16*x  -  11400/x²  = 0

16*x³  =  11400     ⇒   x³  =  11400/16

x³ =  712,5

x  =  8,93  cm

and    h   =  475 / (8,93)²      ⇒      h  =  5,95  cm

C(min)  =  8*79,77  +  4* ( 8,93)*5,95

C(min)  =  638,16  +  212,53

C(min)  =  850,69 cents

To check if value x = 8,93 would make C(x) minimum we go to the second derivatives

C´´(x) =  16  +  22800/x³ > 0

Then we have a minimum of C at  x = 8,93

4 0
4 years ago
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