Answer:
First, plot points A & B on a graph.
Collinear just means 3 or more points in a straight line (because just 2 points are always collinear, since a straight line can always be drawn through two points.
The instructions don't state a specific area in which points C & D have to be in, so you can put them anywhere, as long as they are collinear with each other, but not any other points,
- i.e. putting three units up and two units left of points A & B
So let's make up some points for C & D that are on a straight line.
- Remember, this line does <em>not</em> have to be horizontal! As long as it's a straight line, any direction will do.
Here are some points that you can choose from:
- C(-1, 1); D(-1, -1)
- C(4, 5); D(4, -5)
- C(3, 4); D(3, 5)
- Anything that doesn't fall on x=2 or y=±3.
For "F" just pick a set of coordinates off to the side and label it
You can even use half values if you want:
- (0.5, 3.2)
- (1.2, -4.1)
- (-9.1, -0.2)
As long as your plotted points meet the criteria:
- C & D are <em>Collinear</em>
- A, B, C, D, & F must not land on the same straight line.
Multiply 1/6 by 1/6 by 1/6 essentially
(1/6)^3
1/216
Answer:
Step-by-step explanation:
g(h(x))=g(3x + 7). Since h(x)=3x + 7
g(h(x))= 2(3x + 7) - 5
g(h(x))= 6x + 14 -5
=6x +9
Your post would be clearer if you'd please put each function on its own line:
f(x) = (x + 4)2 + 4
f(x) = –(x + 4)2 + 4
f(x) = (x – 4)2 – 4
f(x) = –(x – 4)2 – 4
Also, use "^2" to denote "squaring." x2 has no meaning.
f(x) = (x + 4)^2 + 4 has a parabolic graph with vertex (-4,4). It increases steadily once x is greater than -4. Reject this choice.
f(x) = –(x + 4)^2 + 4 has a parab. graph with vertex (-4,4) also. It decreases steadily once x is greaster than -4. This is the answer.
Analyze the other 2 possible answers in the same way, please.
answer:
x = 4
y = -3
steps :
x = 10 + 2y
x + y = 1
2y = x - 10 -> y = 1/2x - 5
x + y = 1 -> y = 1 - x
since theyre both equal to y they are equal to each other
1/2x - 5 = 1 - x
3/2x = 6
x = 4
plug 4 back where x is
y = 1 - 4
y = -3
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