Answer:
Option C.) B
Step-by-step explanation:
we have
y > -2x+10 -----> inequality A
The solution of the inequality A is the shaded area above the dashed line y=-2x+10
The slope of the dashed line is negative m=-2
The y-intercept of the dashed line is (0,10)
The x-intercept of the dashed line is (5,0)
y > (1/2)x-2 -----> inequality B
The solution of the inequality B is the shaded area above the dashed line
y= (1/2)x-2
The slope of the dashed line is positive m=1/2
The y-intercept of the dashed line is (0,-2)
The x-intercept of the dashed line is (4,0)
using a graphing tool
The solution of the system of inequalities is the shaded area
see the attached figure
Points B and I are solution to the system of inequalities
If a 16-fluid-ounce bottle of juice costs $2.00, the unit cost would be about $0.13 per ounce. 16/2=8, 1/8=0.125, 0.125=> $0.13.
Answer:
P = 6w + 18
Step-by-step explanation:
A rectangle is a plane shape having a LENGTH and a WIDTH.
Length (l) = w + 4
Width (w) = 2w + 5
To write a simplified equation in terms of w to represent the total length, let's used the idea of a PERIMETER of a RECTANGLE.
Perimeter (P) = 2 ( l + b)
Where l = length= w + 4
Where b = width = 2w + 5
P = 2( w + 4 + 2w + 5)
P = 2( 3w + 9)
P = 6w + 18
Answer:
The answer is B
Step-by-step explanation:
Because 175% means its more than what it was before. Hope this helped!!
Answer:
(a) The probability of more than one death in a corps in a year is 0.1252.
(b) The probability of no deaths in a corps over 7 years is 0.0130.
Step-by-step explanation:
Let <em>X</em> = number of soldiers killed by horse kicks in 1 year.
The random variable
.
The probability function of a Poisson distribution is:
![P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...](https://tex.z-dn.net/?f=P%28X%3Dx%29%3D%5Cfrac%7Be%5E%7B-%5Clambda%7D%5Clambda%5E%7Bx%7D%7D%7Bx%21%7D%3B%5C%20x%3D0%2C1%2C2%2C...)
(a)
Compute the probability of more than one death in a corps in a year as follows:
P (X > 1) = 1 - P (X ≤ 1)
= 1 - P (X = 0) - P (X = 1)
![=1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252](https://tex.z-dn.net/?f=%3D1-%5Cfrac%7Be%5E%7B-0.62%7D%280.62%29%5E%7B0%7D%7D%7B0%21%7D-%5Cfrac%7Be%5E%7B-0.62%7D%280.62%29%5E%7B1%7D%7D%7B1%21%7D%5C%5C%3D1-0.54335-0.33144%5C%5C%3D0.12521%5C%5C%5Capprox0.1252)
Thus, the probability of more than one death in a corps in a year is 0.1252.
(b)
The average deaths over 7 year period is: ![\lambda=7\times0.62=4.34](https://tex.z-dn.net/?f=%5Clambda%3D7%5Ctimes0.62%3D4.34)
Compute the probability of no deaths in a corps over 7 years as follows:
![P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130](https://tex.z-dn.net/?f=P%28X%3D0%29%3D%5Cfrac%7Be%5E%7B-4.34%7D%284.34%29%5E%7B0%7D%7D%7B0%21%7D%3D0.01304%5Capprox0.0130)
Thus, the probability of no deaths in a corps over 7 years is 0.0130.