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Marianna [84]
3 years ago
12

 A map of a highway has a scale of 2 inches equals 33 miles. The length of the highway on the map is 6 inches. There are 11 rest

stops equally spaced on the​ highway, including one at each end. You are making a new map with a scale of 1 inch equals 30 miles. How far apart are the rest stops on the new​ map?
(nvm)
Mathematics
1 answer:
vfiekz [6]3 years ago
7 0

Answer:

The answer is "0.975"

Step-by-step explanation:

Please find the complete question in the attched  file.

Find the remaining distance inside the original map

\to \frac{9}{6}=1.5  \ in

Dividing the value by 6 because there are 7 rest stop:

\to \frac{2 \ inches}{39 \ inches} =\frac{1.5 \ inches}{x \ miles}\\\\\to x=39 \times \frac{1.5}{2}\\\\\to  x=29.25 \ miles

Finding the diatance of the rest stop in the new map

Using proportion:

\to \frac{1 \ inches}{30 \ miles} =\frac{x \ inches}{ 29.25 \ miles}\\\\\to  x= \frac{29.25}{30}\\\\\to  x=0.975 \ in

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Analyze the diagram below and complete the instructions that follow. Find a, b, and c.
ahrayia [7]

Answer:

<u>The correct answer is the letter C. </u>

Step-by-step explanation:

We can use the following trigonometric identity:

cos(60)=\frac{6}{b} (1)

cos(45)=\frac{c}{b} (2)

Solving each equation by b and equaling we have:

\frac{6}{cos(60)}=\frac{c}{cos(45)}

\frac{6}{cos(60)}=\frac{c}{cos(45)}

Let's recall that:

cos(45)=\frac{1}{\sqrt{2}}

cos(60)=\frac{1}{2}

Then we have:

c=\frac{cos(45)*6}{cos(60)}

c=\frac{2*6}{\sqrt{2}}

c=\frac{12}{\sqrt{2}}

c=6\sqrt{2}

Using equation (1) we can find b.

cos(60)=\frac{6}{b}  

b=12      

Finally, we can find a using the next equation:

tan(60)=\frac{a}{6}

a=6*tan(60)

a=6\sqrt{3}

<u>Therefore, the correct answer is the letter C. </u>

I hope it helps you!

5 0
2 years ago
HELPPP!!!!!! URGENT!!!​
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Answer:

20

Step-by-step explanation:

x = price

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==> x = 20

==> y = 27

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3 years ago
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