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Alexxandr [17]
3 years ago
8

Would any three squares form the sides of a right triangle? Explain.

Mathematics
2 answers:
ella [17]3 years ago
8 0
The sum of the side lengths of the two smaller squares is equal to the side length of the large square. ... The three squares shown joined at their vertices to form a right triangle.
lara [203]3 years ago
3 0
The sum of the areas would be two small squares so no
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Aremethic sequences 5, 7, 9, 11, 13
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The sequence is all odd numbers. the next will be 15, 17, 19, 21, etc...
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3 years ago
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What is the measure of ACB in O below?​
Nezavi [6.7K]

Answer:

A

Step-by-step explanation:

The central angle is equal to the arc that subtends it , then

arc AB = 30°

arc ACB = 360° - 30° = 330° → A

7 0
3 years ago
What is the formula for the expected number of successes in a binomial experiment with n trials and probability of success​ p? C
charle [14.2K]

Answer:

(D)E[ X ] =np.

Step-by-step explanation:

Given a binomial experiment with n trials and probability of success​ p,

f(x)=\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}, 0\leq  x\leq n

E(X)=\sum_{x=0}^{n}xf(x)= \sum_{x=0}^{n}x\left(\begin{array}{c}n\\k\end{array}\right)p^x(1-p)^{n-x}

Since each term of the summation is multiplied by x, the value of the term corresponding to x = 0 will be 0. Therefore the expected value becomes:

E(X)=\sum_{x=1}^{n}x\left(\begin{array}{c}n\\x\end{array}\right)p^x(1-p)^{n-x}

Now,

x\left(\begin{array}{c}n\\x\end{array}\right)= \frac{xn!}{x!(n-x)!}=\frac{n!}{(x-)!(n-x)!}=\frac{n(n-1)!}{(x-1)!((n-1)-(x-1))!}=n\left(\begin{array}{c}n-1\\x-1\end{array}\right)

Substituting,

E(X)=\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^x(1-p)^{n-x}

Factoring out the n and one p from the above expression:

E(X)=np\sum_{x=1}^{n}n\left(\begin{array}{c}n-1\\x-1\end{array}\right)p^{x-1}(1-p)^{(n-1)-(x-1)}

Representing k=x-1 in the above gives us:

E(X)=np\sum_{k=0}^{n}n\left(\begin{array}{c}n-1\\k\end{array}\right)p^{k}(1-p)^{(n-1)-k}

This can then be written by the Binomial Formula as:

E[ X ] = (np) (p +(1 - p))^{n -1 }= np.

5 0
3 years ago
Where are the asymptotes of f(x) = tan(4x − π) from x = 0 to x = π/ 2 ?
Aneli [31]
That answer was (B)................
3 0
3 years ago
I need help please help me
harkovskaia [24]
We substitute in c using 9, it will be as follows:
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