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Alex73 [517]
3 years ago
12

Help please! Photo below!

Mathematics
2 answers:
sergiy2304 [10]3 years ago
4 0

Answer:

1. 128 (B)

2. 1024 (A)

3. 243 (F)

4. 256 (C)

zhuklara [117]3 years ago
3 0

Answer:

1. 128 or B

2. 1024 or A

3. 243 or F

4. 256 or c

Step-by-step explanation:

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What is the length of side x? If necessary, round your answer to two decimal places PLEASE HELP
Bess [88]
Use the pythagorean theorem
a squared plus b squared equals c squared where c is the length of the hypotenuse and a and b are the lengths of the legs in a right triangle
c^2-b^2=31^2-23^2=432
432=a^2
a=approx 20.7846
5 0
3 years ago
Read 2 more answers
Point (2, -4) is reflected across the x-axis. What are<br> the coordinates of its image?
Zina [86]

The coordinates of the image of point (2 , -4) after reflection across

the x-axis is (2 , 4)

Step-by-step explanation:

Let us revise the reflection of a point

1. If point (x , y) reflected across the x-axis, then its image is (x , -y)

2. If point (x , y) reflected across the y-axis, then its image is (-x , y)

3. If point (x , y) reflected across the line y = x, then its image is (y , x)

4. If point (x , y) reflected across the line y = -x, then its image is (-y , -x)

∵ Point (2, -4) is reflected across the x-axis

∵ Point (x , y) reflected across the x-axis, then its image is (x , -y)

- Chang the sign of the y-coordinate of the point to find its image

∵ The y-coordinate of the point is -4

∴ The y-coordinate of the image is 4

∴ The image of the point (2 , -4) is (2 , 4) after reflection across the

   x-axis

The coordinates of the image of point (2 , -4) after reflection across

the x-axis is (2 , 4)

Learn more:

You can learn more about reflection in brainly.com/question/5017530

#LearnwithBrainly

7 0
3 years ago
Read 2 more answers
Estimate the product by rounding each number to its greatest place value of 2342.7 times 784.3​
Lubov Fominskaja [6]

Answer:

The answer is 1,837,379.61 but if you round, it's 2,000,000,.00.Hope this helps!

3 0
3 years ago
Triangle ABC was dilated and translated to form similar triangle A'B'C'.
kompoz [17]

we have that

A(0,2)\ B(2,2)\ C(2,0)\\A'(-4,-1)\ B'(1,-1)\ C'(1,-6)

we know that

Triangles ABC and A'B'C' are similar

Step 1

Find the distance AB and distance A'B' with the formula

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

a) distance AB

dAB=\sqrt{(2-2)^{2}+(2-0)^{2}}

dAB=\sqrt{(0)^{2}+(2)^{2}}

dAB=2\ units

b) distance A'B'

dA'B'=\sqrt{(-1+1)^{2}+(1+4)^{2}}

dA'B'=\sqrt{(0)^{2}+(5)^{2}}

dA'B'=\sqrt{25}\ units

dA'B'=5\ units

Step 2

Find the scale factor

scale\ factor= \frac{measure\ A'B'}{measure\ AB} \\ \\ scale\ factor=\frac{5}{2} \\ \\ scale\ factor=2.5

therefore

the answer is

the scale factor of the dilation is equal to 2.5

8 0
4 years ago
Read 2 more answers
A farmers field is 32 feet on each side. How many square feet does she have to plow?
11111nata11111 [884]

Answer:

1024 sq. ft.

Step-by-step explanation:

Each side is 32 feet long, so you would have to multiply 32 by 32, assuming all the sides are the same length.

3 0
3 years ago
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