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Yuliya22 [10]
3 years ago
5

What has the greater density, a cube of water measuring by by and having a mass of or a block of plastic measuring 2cm by 3cm by

with a mass of ? Round any decimal to nearest tenth
Mathematics
1 answer:
stepladder [879]3 years ago
7 0
The greater density to measure by having a mass of 2cm or 3cm
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Graph the feasibility region represented by the given inequalities and find the maximum profit if P = 4x + 5y. x ≥ 5 y ≤ 10 2x -
Brilliant_brown [7]

First, graph the three inequalities:  x ≥ 5  ,  y ≤ 10  ,  2x - y  ≤ 8

Next, look for the 3 intersections (vertices) of the lines: (5, 2)  ,  (5, 10)   ,  (9, 10)

Finally, input the vertex coordinates into P = 4x + 5y and look for the biggest #.

(5, 2):  4(5) + 5(2)  = 20 + 10  = 30

(5, 10): 4(5) + 5(10)  = 20 + 50  = 70

(9, 10): 4(9) + 5(10)  = 36 + 50  = 86

Answer: maximum profit = 86


8 0
3 years ago
Combine like terms in the following expression: 4 + 3(1−3m)
zmey [24]

it is impossible to combine like terms. In order to combine like terms you must have like x+x you cant have like 1+x

5 0
3 years ago
Read 2 more answers
Divide $70 into 1:2:4
irina1246 [14]
$70 into 1:2:4

1+2+4 = 7
7 parts= $70
1 part  = $70/7 ($70 divided by 7)
1:2:4   = $10:$20:$40

answer= $10:$20:$40

Hope this helps!! :)
5 0
3 years ago
What is the area of a quadrilateral ABCD, if AB = 5 cm, BC = 13 cm, CD = 9 cm, DA = 15 cm, AC = 12 cm?
Setler [38]
<span>ABCD is a quadrilateral with angle ABC a right angle. The point D lies on the perpendicular bisector of AB. The coordinates of A and B are (7, 2) and (2, 5) respectively. The equation of line AD is y = 4x − 26. find the area of quadrilateral ABCD</span>
4 0
3 years ago
On Aaron’s farm, 1/10 of the animals are cows, ⅖ of the animals are chickens,
Ray Of Light [21]

Answer:

There are 5 pigs on Aaron's farm

Step-by-step explanation:

1. Start with 40 animals

2. 1/10 of the animals are cows, so divide 40 by 10 and you will find that 4 of the animals are cows

3. 2/5 of the animals are chickens, so multiple 40 by 2 to get 80 and then divide 80 by 5 and you will find that 16 of the animals are chickens

4. Subtract the 4 cows and 16 chickens from the 40 total animals and you find there are 20 more animals that are neither cows nor chickens

5. Of the 20 remaining animals, 1/4 are pigs, so divide 20 by 4 and you will find that there are 5 pigs

6 0
3 years ago
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