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3 years ago

5

What has the greater density, a cube of water measuring by by and having a mass of or a block of plastic measuring 2cm by 3cm by

with a mass of ? Round any decimal to nearest tenth

1 answer:

stepladder [879]3 years ago

7 0

The greater density to measure by having a mass of 2cm or 3cm

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PETS Last month, Hao's dog ate 40 cans

zimovet [89]

Answer:

8 cans

Step-by-step explanation:

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2 years ago

2. Evaluate each function at the specific value

Oliga [24]

F(6) says “take f(x) = -4x + 11 and put 6 in for every x-value and then clean it up.”

f(6) = -4(6) + 11

      = -24 + 11

      = -13

f(x) = -1 says “set your function equal to -1 and solve for x”

    f(x) = -1

-4x+11 = -1

-4x = -12

        x = 3

So f(3) = -1.

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2 years ago

A rectangle is shown. 2 right triangles sit on the top of the rectangle. The sides of the rectangle are congruent with 2 sides o

Salsk061 [2.6K]

Answer:3x2

Step-by-step explanation:

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2 years ago

Read 2 more answers

Write an equivalent expression for 5a+30

Elena-2011 [213]

We can express it at 5 (a+6)

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3 years ago

Read 2 more answers

Let x be the average number of employees in a group health insurance plan, and let y be the average administrative cost as a per

Step2247 [10]

A scatter diagram has points that show the relationship between two sets of data.

We have the following data,

$\left\begin{array}{ccccccc}\mathrm{x}&3&7&15&32&74\\\mathrm{y}&40&35&30&25&17\end{array}\right$

where <em>x</em> is the average number of employees in a group health insurance plan and <em>y</em> is the average administrative cost as a percentage of claims.

To make a scatter diagram you must, draw a graph with the independent variable on the horizontal axis (<em>in this case x</em>) and the dependent variable on the vertical axis (<em>in this case y</em>). For each pair of data, put a dot or a symbol where the x-axis value intersects the y-axis value.

Linear regression is a way to describe a relationship between two variables through an equation of a straight line, called line of best fit, that most closely models this relationship.

To find the line of best fit for the points, follow these steps:

Step 1: Find $X\cdot Y$ and $X\cdot X$ as it was done in the below table.

Step 2: Find the sum of every column:

$\sum{X} = 131 ~,~ \sum{Y} = 147 ~,~ \sum{X \cdot Y} = 2873 ~,~ \sum{X^2} = 6783$

Step 3: Use the following equations to find intercept a and slope b:

$\begin{aligned} a &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} = \frac{ 147 \cdot 6783 - 131 \cdot 2873}{ 5 \cdot 6783 - 131^2} \approx 37.05 \\ \\b &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} = \frac{ 5 \cdot 2873 - 131 \cdot 147 }{ 5 \cdot 6783 - \left( 131 \right)^2} \approx -0.292\end{aligned}$

Step 4: Assemble the equation of a line

$\begin{aligned} y~&=~a ~+~ b \cdot x \\y~&=~37.05 ~-~ 0.292 \cdot x\end{aligned}$

6 0

3 years ago