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iVinArrow [24]
3 years ago
6

Point S is located at (-3,2) on the coordinate plane. Point S is reflected over the y-

Mathematics
1 answer:
grigory [225]3 years ago
3 0

Answer:

(3,2)

Step-by-step explanation:

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How is the interquartile range calculated?
Nastasia [14]
It is the difference between the third and the first quartile
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3 years ago
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-2x + y = 0 <br><br> -7x + 3y = 2<br> ​
dsp73
This is a system of equations.
First, you set everything in terms of y.
Take the first equation and move set everything equal to y
y=0+2x
Since it’s 0, you don’t need to put it, so
y=2x works.
Then, you plug y=2x into the bottom equation, for the y.
-7x +3(2x)=2. You do this because now you have the same variable for both and it can be solved easily.
Then you can simplify.
-7x+3x = 2
Then combine like terms.
-4x = 2
Divide by -4 on each side.
x = -1/2
So, now that you have x, you can plug in your x-value back into the top equation.
-2(-1/2) + y = 0
Combine like terms
1+y=0
Get y by itself
y=-1
There you have it!
You can check by plugging in both values to any of the equations. We will use the top one here.
-2(-1/2) + (-1) =0
+1 + -1 = 0
It works!
So,
X= -1/2
Y= -1
Please rate me Brainliest answer :)
3 0
3 years ago
Read 2 more answers
When running a 100 meter race matt reaches his maximum speed when he is 40 meters from the starting line, and 7 seconds have ela
ch4aika [34]

Answer:

Step-by-step explanation:

time after 40 meters to 80 meters=12-7=5 s

distance=80-40=40 m

max. speed=40/5=8 m/s

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3 years ago
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Whats the intrgral of <img src="https://tex.z-dn.net/?f=%20%5Cint%20%20%5Cfrac%7Bx%5E2%2Bx-3%7D%7B%28x%5E3%2Bx%5E2-4x-4%29%5E2%7
rosijanka [135]
\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx

Notice that x^3+x^2-4x-4=x^2(x+1)-4(x+1)=(x-2)(x+2)(x+1). Decompose the integrand into partial fractions:

\dfrac{x^2+x-3}{(x-2)^2(x+2)^2(x+1)^2}
=\dfrac1{3(x+1)}-\dfrac{11}{32(x+2)}-\dfrac1{3(x+1)^2}-\dfrac1{16(x+2)^2}+\dfrac1{96(x-2)}+\dfrac1{48(x-2)^2}

Integrating term-by-term, you get

\displaystyle\int\frac{x^2+x-3}{(x^3+x^2-4x-4)^2}\,\mathrm dx
=-\dfrac1{48(x-2)}+\dfrac1{3(x+1)}+\dfrac1{16(x+2)}+\dfrac1{96}\ln|x-2|+\dfrac13\ln|x+1|-\dfrac{11}{32}\ln|x+2|+C
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3 years ago
What is-3/7x-2 in standard form
Eddi Din [679]
If you are given y = (-3/7)x - 2 and you want it in the form Ax+By = C, then...

y = (-3/7)x-2
7*y = 7*( (-3/7)x-2) ... multiply both sides by 7
7y = -3x-14 ... distribute and multiply
7y+3x = -3x-14+3x ... add 3x to both sides
3x+7y = -14

The standard form equation is 3x+7y = -14
3 0
3 years ago
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